Question

Radiochemical techniques are useful in estimating the solubility product of many compounds. In one experiment, 70.0 mL of 0.030 M AgNO3 solution containing a silver isotope with a radioactivity of 74,025 counts per min per mL were mixed with 300.0 mL of a 0.080 M NaIO3 solution. The mixed solution was diluted to 700.0 mL and filtered to remove all of the AgIO3 precipitate. The remaining solution was found to have a radioactivity of 44.4 counts per min per mL.

Answer 1

Given:

V1 = 70 ml
C1 = 0.030 M AgNO3 solution
Radioactivity: 74,025 counts/min mL 

V2 = 300 ml
C2 = 0.080 M NaIO3

Balanced Equation:

AgNO3 + NaIO3 ==> NaNO3 + AgIO3

Then the solution is diluted to 700 ml, the dilution factor is (300 + 70) / 700. This will be used in calculating the solubility of the product. 
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