Answer:
Explanation:
The following code was written in Java. The code contains the Employee class which contains the two variables (name, salary), the constructor, getter and setter methods for both variables, and an overwritten toString method. It also contains a tester class with the main method inside and creates a Employee object and initializes it. Then it calls the toString method. The output can be seen in the attached image below. Due to technical difficulties I have added the code as a txt file below.
The pseudocode to calculate the average of the test scores until the user enters a negative input serves as a prototype of the actual program
<h3>The errors in the pseudocode</h3>
The errors in the pseudocode include:
- Inclusion of unusable segments
- Incorrect variables
- Incorrect loops
<h3>The correct pseudocode</h3>
The correct pseudocode where all errors are corrected and the unusable segments are removed is as follows:
start
Declarations
num test1
num test2
num test3
num average
output "Enter score for test 1 or a negative number to quit"
input test1
while test1 >= 0
output "Enter score for test 2"
input test2
output "Enter score for test 3"
input test3
average = (test1 + test2 + test3) / 3
output "Average is ", average
output "Enter score for test 1 or a negative number to quit"
input test1
endwhile
output "End of program"
stop
Read more about pseudocodes at:
brainly.com/question/11623795
num1 = float(input("Enter the first number: "))
num2 = float(input("Enter the second number: "))
operation = input("Which operation are you performing? (a/s/m/d) ")
if operation == "a":
print("{} + {} = {}".format(num1, num2, num1+num2))
elif operation == "s":
print("{} - {} = {}".format(num1, num2, num1-num2))
elif operation == "m":
print("{} * {} = {}".format(num1, num2, num1*num2))
elif operation == "d":
print("{} / {} = {}".format(num1, num2, num1/num2))
I hope this helps!
Answer:
Broadcast message
Explanation:
The network models like OSI and TCP/IP suites have standard layers and protocols that governs the communication of end devices in a network.
The TCP/IP suite model has four layers which are application, transport, internet and network access layers. The network access does the work of both the data-link and physical layer of the OSI model.
When the packet is encapsulated in a data-link header and trailer, and needs to be sent to another unknown host, a broadcast message is sent to all the computers in the network to retrieve the remote host address for a unicast transmission to take place.
Answer:
The decimal value of 101₂² base 2 = 25 base 10
Explanation:
The number 101₂² in decimal value is found as follows;
101₂ × 101₂ = 101₂ + 0₂ + 10100₂
We note that in 101 + 10100 the resultant 2 in the hundred position will have to be converted to a zero while carrying over 1 to the thousand position to give;
101₂ + 0₂ + 10100₂ = 11001₂
Therefore;
101₂² = 11001₂
We now convert the result of the square of the base 2 number, 101², which is 11001₂ to base 10 as follows;
Therefore converting 11001₂ to base 10 gives;
11001₂= 1 × 2⁴ + 1 × 2³ + 0 × 2² + 0 × 2 ¹ + 1 × 2⁰
Which gives;
16 + 8 + 0 + 0 + 1 = 25₁₀.
