We have that if the sample size is greater than 5% of the entire population, a finite population correction factor (fpc) is multiplied with the standard error :

fpc = $\sqrt{\frac{N -n}{N -1} }$

We know that N = 250 n = 91, replacing:

fpc = $\sqrt{\frac{250 - 91}{250 -1} }$

fpc = 0.799

Now, the formula would then be:

SE = $\sqrt{\frac{p * (1 -p)}{n} }$ *fpc

Now replacing, knowing that p = 0.12

SE= $\sqrt{\frac{0.12 * (1 - 0.12)}{91} }$ *0.799

SE = 0.0272

So the standard error of the proportion is 0.0272

6 0

3 years ago

Solve for pizza in the pie chart!

solniwko [45]

Answer:

Step-by-step explanation:

30% of the pie chart is pizza. 30% of 80 = 0.3 * 80 = 24

6 0

2 years ago

Read 2 more answers

F(x) = 2x + 3g(x) = 2x² + 6x + 13Find: (gºf)(x)

Butoxors [25]

Answer:

The function (gof)(x) is;

$(g\circ f)(x)=8x^2+36x+49$

Explanation:

Given the functions;

$\begin{gathered} f(x)=2x+3 \\ g(x)=2x^2+6x+13 \end{gathered}$

Solving for the function;

$(g\circ f)(x)=g(f(x))$

so, we have;

$\begin{gathered} g(f(x))=2(f(x))^2+6(f(x))+13 \\ g(f(x))=2(2x+3)^2+6(2x+3)+13 \\ g(f(x))=2(4x^2+12x+9)^{}+6(2x)+6(3)+13 \\ g(f(x))=8x^2+24x+18^{}+12x+18+13 \\ g(f(x))=8x^2+24x^{}+12x+18+18+13 \\ g(f(x))=8x^2+36x+49 \end{gathered}$

Therefore, the function (gof)(x) is;

$(g\circ f)(x)=8x^2+36x+49$

5 0

1 year ago