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Iteru [2.4K]
3 years ago
13

Plsss help me no links

Mathematics
2 answers:
Sindrei [870]3 years ago
8 0

Answer:

D) 42.16

Total: $553.13

Step-by-step explanation:

Multiply the subtotal, 510.97, by 8.25%. To do that just turn the 8.25% into a decimal which is 0.0825. The answer to that would be 42.155025 and rounded it would be 42.16 so the tax would be $42.16.

The total to the entire thing would be $553.13 since you just add the tax and subtotal together.

frutty [35]3 years ago
5 0

Answer: D 42.16

Step-by-step explanation: 510.97(subtotal)x8.25%(sales tax)=42.16

Don’t forget to move the decimal 2 places to the left on the sales tax when multiplying(.0825)

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The quotient of a and 5
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\frac{a}{5}

Step-by-step explanation:

That would be a divide by 5: \frac{a}{5}

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Find the equation of the line <br> y= x+
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The following number line contains the points A, B, C, D, and E.
Troyanec [42]

The probability that a point chosen at random on AE is on AB is 1/5

<h3>What is a Number Line?</h3>

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Based on the keen observation, there are 10 line segments that have an equal length and from the two points, there are two equal line segments,

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3 0
2 years ago
Now, lets evaluate the same integral using power series. first, find the power series for the function f(x = \frac{32}{x^2+4}. t
BlackZzzverrR [31]
No idea what the previous part of the problem is, but you have

f(x)=\dfrac{32}{x^2+4}=\dfrac8{1-\left(-\frac{x^2}4\right)}=\displaystyle8\sum_{n\ge0}\left(-\frac{x^2}4\right)^n
f(x)=\displaystyle8\sum_{n\ge0}\left(-\dfrac14\right)^nx^{2n}

which is valid for \left|-\dfrac{x^2}4\right|, or |x|. So the integral from 0 to 2 is

\displaystyle\int_0^2f(x)\,\mathrm dx=\int_0^28\sum_{n\ge0}\left(-\frac14\right)^nx^{2n}\,\mathrm dx
=\displaystyle8\sum_{n\ge0}\left(-\frac14\right)^n\int_0^2x^{2n}\,\mathrm dx

Note that since the power series only converges on the interval if x is strictly less than 2, which means we have to treat this as an improper integral.

=\displaystyle8\sum_{n\ge0}\left(-\frac14\right)^n\lim_{t\to2^-}\int_0^tx^{2n}\,\mathrm dx[/tex]
=\displaystyle8\sum_{n\ge0}\left(-\frac14\right)^n\lim_{t\to2^-}\frac{x^{2n+1}}{2n+1}\bigg|_{x=0}^{x=t}
=\displaystyle8\sum_{n\ge0}\frac{(-1)^n}{2^{2n}(2n+1)}\lim_{t\to2^-}t^{2n+1}
=\displaystyle16\sum_{n\ge0}\frac{(-1)^n}{2n+1}
=16-\dfrac{16}3+\dfrac{16}5-\dfrac{16}7+\dfrac{16}9+\cdots
6 0
3 years ago
Hello i need help fast​
Ber [7]

Answer:

486

Step-by-step explanation:

6 0
3 years ago
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