All categories

3 years ago

Match the key aspect of a function's graph with its meaning.

Mathematics

1 answer:

Margarita [4]3 years ago

5 0

Answer:

Part 1) Intervals of the domain where the graph is above the x-axis (f(x) > 0)

Part 2) location on graph where input is zero (y-intercept)

Part 3) location on graph where output is zero (x-intercept)

Part 4) Intervals of the domain where the graph is below the x-axis (f(x) < 0)

Step-by-step explanation:

<u><em>Verify each case</em></u>

Part 1) we have

Intervals of the domain where the graph is above the x-axis

we know that

If the graph is above the x-axis, then the value of f(x) is positive

therefore

f(x) > 0

Part 2) we have

location on graph where input is zero

Let

x ---> the independent variable or input value

f(x) ---> the dependent variable or output value

we know that

The y-intercept is the value of f(x) (output value) when the value of x (input value) is zero

therefore

y-intercept

Part 3) we have

location on graph where output is zero

Let

x ---> the independent variable or input value

f(x) ---> the dependent variable or output value

we know that

The x-intercept is the value of x (input value) when the value of the function f(x) (output value) is zero

therefore

x-intercept

Part 4) we have

Intervals of the domain where the graph is below the x-axis

we know that

If the graph is below the x-axis, then the value of f(x) is negative

therefore

f(x) < 0

You might be interested in

A cold drink is poured out at 52°F. After 2 minutes of sitting in a 72°F room, its temperature has risen to 55°F. Find an equati

I am Lyosha [343]

Answer:

The model for the temperature of the drink can be written as

$T=72-20e^{-0.08t}$

Step-by-step explanation:

For a cold drink in a hotter room, we can say that the rate of change of temperature of the drink is proportional to the difference of temperature between the drink and the room.

We can model that in this way

$\frac{dT}{dt}=k*(T_r-T)$

If we rearrange and integrate

$\int\frac{dT}{(T-Tr)} =-k*\int dt\\\\ln(T-T_r)=-kt+C1\\\\T-T_r=Ce^{-kt}\\\\T=T_r+Ce^{-kt}$

We know that at time 0, the temperature of the drink was 52°F. Then we have:

$T=T_r+Ce^{-kt}\\\\52=72+Ce^0=72+C\\\\C=-20$

We also know that at t=2, T=55°F

$T=T_r+Ce^{-kt}\\\\55=72-20e^{-k*2}\\\\e^{-k*2}=(72-55)/20=0.85\\\\-2k=ln(0.85)=-0.1625\\\\k=0.08$

The model for the temperature of the drink can be written as

$T=72-20e^{-0.08t}$

7 0

4 years ago

Solve the following quadratic equation. Express your answers in exact form.

wlad13 [49]

Answer:

x = (2+√10)/ 3 and x= (2-√10/3)

Step-by-step explanation:

g(x) = -3x² +4x +2

use the quadratic formula x= (-b±√b²-4ac)/2a, when g(x) = ax² +bx +c

x= [-4 ±√4²-4*(-3)*2] / 2*(-3) , solve under the square root

x= (-4 ± √16 +24) / -6 , add under the radical

x= (-4 ±√40) / -6, simplify the square root

x= (-4 ±2√10) /-6, factor -2

x= -2 (2±√10)/-2 *3, simplify -2

x= (2±√10)/3

Therefore,

x = (2+√10)/ 3 and x= (2-√10/3)

5 0

3 years ago

Please show your work. The data modeled by the box plots represents the battery life of two different brand of batteries that Ji

Diano4ka-milaya [45]

(a) Brand X median = 13
Brand Y median = 16

Median is the center dot in the shaded box (in blue color). Look at the Time (h) axis for their values. For Brand X it is 13 whereas for the Brand Y it is 16

(b) If we compare their median values we can see that the difference is 3 hours (16-13 = 3). It means that the Brand Y battery will last longer compared to Brand X battery as Brand Y lasts for 16 hours whereas Brand X battery lasts for 13 hours.

7 0

3 years ago

Use the coordinates if the labled point

jok3333 [9.3K]

It would be C.

HOPE THIS HELPS!!! PLEASE MARK BRAINLIEST!!!

7 0

3 years ago

Write 12 thousands, 8 thousands, 14 hundreds, 7 ones

Leona [35]

12,000

8,000

1400

7

hope this helps

3 0

3 years ago