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podryga [215]
3 years ago
14

Match the key aspect of a function's graph with its meaning.

Mathematics
1 answer:
Margarita [4]3 years ago
5 0

Answer:

Part 1) Intervals of the domain where the  graph is above the x-axis (f(x) > 0)

Part 2) location on graph where input is zero  (y-intercept)

Part 3) location on graph where output is zero  (x-intercept)

Part 4) Intervals of the domain where the  graph is below the x-axis (f(x) < 0)

Step-by-step explanation:

<u><em>Verify each case</em></u>

Part 1) we have

Intervals of the domain where the  graph is above the x-axis

we know that

If the graph is above the x-axis, then the value of f(x) is positive

therefore

f(x) > 0

Part 2) we have

location on graph where input is zero  

Let

x ---> the independent variable or input value

f(x) ---> the dependent variable or output value

we know that

The y-intercept is the value of f(x) (output value) when the value of x (input value) is zero

therefore

y-intercept

Part 3) we have

location on graph where output is zero  

Let

x ---> the independent variable or input value

f(x) ---> the dependent variable or output value

we know that

The x-intercept is the value of x (input value) when the value of the function f(x) (output value) is zero

therefore

x-intercept

Part 4) we have

Intervals of the domain where the  graph is below the x-axis

we know that

If the graph is below the x-axis, then the value of f(x) is negative

therefore

f(x) < 0

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Answer:

D.

Step-by-step explanation:

The equation given takes the point-slope form which is, y - b = m(x - a). Where,

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To find which graph has a line equation of y - 2 = 3(x - 1), look for the points which will give you something almost exactly as the equation if you substitute their values into y - b = m(x - a).

Let's consider option D.

We have a given point (1, 2). a = 1, b = 2.

Substitute these into y - b = m(x - a)

We have:

y - (2) = m(x - (1))

y - 2 = m(x - 1)

As you can see, this looks almost exactly as

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If you want to be certain that option D is the answer, find m by using the coordinates of any other point on the line and plug into y - 2 = m(x - 1) to find m:

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