Question

What is the equation of a line parallel to y = 7x - 8 that passes through (5,-2)?

Answer 1

Answer: y=7x+1

Step-by-step explanation: Find any equation parallel to the line.

Hope this helps you out! ☺

Answer 2

Answer:

The equation of a line parallel to y = 7x - 8 that passes through (5,-2):

:$y=7x-37$

Step-by-step explanation:

Given equation of the line :

y = 7x - 8

Slope intercept form =  y = mx + c

Where = m = Slope of the line

c = intercept on y axis

On comparing the given equation with slope intercept form , we get

m = 7, c = -8

For equation of line which parallel to the line formed by given equation will have same slope because parallel lines have same value of slope.

m' = m= 7

Equation of the line passing from point (5,-2) can be determined by the help of point slop form;

$(y-y_1)=m(x-x_1)$

$(x_1,y_1): (5,-2)$

Slope of the parallel line = m' =7

$(y-(-2))=7(x-5)$

$y+2=7x-35$

$y=7x-37$

The equation of a line parallel to y = 7x - 8 that passes through (5,-2):

:$y=7x-37$