What is the equation of a line parallel to y = 7x - 8 that passes through (5,-2)?
2 answers:
Answer:
The equation of a line parallel to y = 7x - 8 that passes through (5,-2):
:
Step-by-step explanation:
Given equation of the line :
y = 7x - 8
Slope intercept form = y = mx + c
Where = m = Slope of the line
c = intercept on y axis
On comparing the given equation with slope intercept form , we get
m = 7, c = -8
For equation of line which parallel to the line formed by given equation will have same slope because parallel lines have same value of slope.
m' = m= 7
Equation of the line passing from point (5,-2) can be determined by the help of point slop form;
Slope of the parallel line = m' =7
The equation of a line parallel to y = 7x - 8 that passes through (5,-2):
:
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Answer:
The answer is below
Step-by-step explanation:
The question is not complete. The complete question is:
The 12 foot long bed of a dump truck loaded with debris must rise an angle of 30 degrees before the debris will spill out. Approximately how high must the front of the bed rise for the debris to spill out.
Solution:
Let x be the height of the front of the bed rise needed to be raised for the debris to spill out. We can find x using trigonometric identities. That is:
sin θ = opposite / hypotenuse
Using trigonometric identities, we can get that:
sin(30) = x / 12
This gives:
0.5 = x / 12
Cross multiplying the terms to get:
x = 12 * 0.5
x = 6 ft
Therefore the front of the bed rise must be raised 6 ft for the debris to spill out.
