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Amiraneli [1.4K]
3 years ago
7

Suppose that a random number generator randomly generates a number from 1 to 65. Once a specific number is generated, the genera

tor will not select that number again until it is reset. If a person uses the random number generator 65 times in a row without resetting, how many different ways can the numbers be generated?
Mathematics
1 answer:
juin [17]3 years ago
8 0

Answer:

65!

65! = 8. 2547650592 * 10^ 90 approximately

Step-by-step explanation:

A random number generator randomly generates a number from 1 to 65.

Once a specific number is generated, the generator will not select that number again until it is reset.

The number of ways it can be used is = 65!

65! = 8. 25476505* 10^ 90 approximately

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3 years ago
Find the similarity ratio and the ratio of perimeters for two regular octagons with areas of 18in2 and 50in2
sweet-ann [11.9K]

Answer:

3. 3 : 5; 3: 5

Step-by-step explanation:

First, let's find the leght of the sides of each octagon.

A= 18in^{2}

The area of an octagon is defined by

A=2(1+\sqrt{2})l^{2}

Replacing the area

18=2(1+\sqrt{2})l^{2}\\\frac{18}{2(1+\sqrt{2})} =l^{2}\\l=\sqrt{\frac{18}{3.4} } \approx 2.3 \ in

Therefore, the side of the first octagon is 1.6 inches long.

Its perimeter is: P=8(2.3in)=18.4in

A=50 in^{2}

50=2(1+\sqrt{2})l^{2}\\\frac{50}{2(1+\sqrt{2})} =l^{2}\\l=\sqrt{\frac{50}{3.4} } \approx 3.8 \ in

Therefore, the side of the second octagon is 3.8 inches long.

Its perimeter is P=8(3.8in)=30.4in.

Now, let's divide to find each ratio:

\frac{3.8}{2.3} \approx 1.65 (the ratio between sides).

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3 years ago
Read 2 more answers
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