Answer:
-445/month
Step-by-step explanation:
I think that what you would do is divide -5,341 by 12, which gives you -445
5x + 50 +x
= 5x*2( square ) + 50
Answer:
<h2>107 and 73</h2><h2 />
Step-by-step explanation:
supplementary angle
7x + 9 + 5x + 3 = 180
12x = 180 - 3 - 9
x = 168 / 12
x = 14
plugin x=14 into the equation
= 7x + 9
= 7(14) + 9
= 107°
plugin x=14 into the equation
= 5x + 3
= 5(14) + 3
= 73°
Answer:
Find the amplitude of a sine or cosine function. Find the period ... Question: What effect will multiplying a trigonometric function by a ... same as the graph of y = sin x and y = cos x, respectively, stretched ... With both graphs to look at, it is easier to see what ... the graph. Question: What happens if we allow the input variable, x. A graph of a cosine curve is shown with attributes labeled. ... Use trigonometric (sine, cosine) functions to model and solve problems; justify results. a) Solve ... Amplitude - How far above or below the axis of the wave a sine or cosine function goes ... Note that the amplitude is always positive, even if the coefficient is negative.
Step-by-step explanation:
Remember
(x^m)(x^n)=x^(m+n)
and difference of 2 perfect squres
(a²-b²)=(a-b)(a+b)
and sum or difference of 2 perfect cubes
so
(x^3)(x^3)(x^3)=x^(3+3+3)=x^9
so
x^9=3*3*x^3
x^9=9x^3
minus 9x^3 both sides
0=x^9-9x^3
factor
0=(x^3)(x^6-9)
factor difference of 2 perfect squraes
0=(x^3)(x^3-3)(x^3+3)
factor differnce or sum of 2 perfect cubes (force 3 into (∛3)³)
0=(x³)(x-∛3)(x²+x∛3+∛9)(x+∛3)(x²-x∛3+∛9)
set each to zero
x³=0
x=0
x-∛3=0
x=∛3
x²+x∛3+∛9=0 has no solution
x+∛3=0
x=-∛3
x²-x∛3+∛9=0 has no solution
so the solutions are
x=-∛3, 0, ∛3
