Answer:
1) D
2) 10
Step-by-step explanation:
sin(30) = opposite/hypotenuse
sin(30) = 5/x
½ = 5/x
x = 5/0.5
x = 10
Answer:
x = -3 and x = -3/2
Step-by-step explanation:
After writing down the polynomial, split it; put a line between 3x^2 and -18x. Look and 2x^3 + 3x^2 and -18x - 27 separately and factor them both:
p(x) = 2x^3 + 3x^2 <u>- 18x -27</u>
p(x) = x^2(2x+3) <u>-9(2x+3)</u>
Now notice how x^2 and -9 have the same factor (2x+3). That means x^2 and -9 can go together:
p(x) = (x^2 - 9)(2x+3)
Factor it once more because there's a difference of squares:
p(x) = (x+3)(x-3)(2x+3)
Now just plug in whatever makes the each bracket equal 0:
x = -3, x = 3, and x = -3/2
Those are your zeros.
Answer:
r= d/2 => 12/2 => 6
a= πR²
a= 3.14×{6}²
a= 113.04 square yard (yd²)
or
a= 94.51 m²
First solve for g(1)
Plug in 1 for the equation g(x)
g(1) = -(1) + 4
g(1) = 3
Now plug 3 in for f(x)
f(3) = 3(3)^2 + 4(3) + 1
f(3) = 3(9) + 12 + 1
f(3) = 27 + 12 + 1
f(3) = 40
Solution: f(g(1)) = 40
9514 1404 393
Answer:
- positive
- negative
- decreasing
- increasing
Step-by-step explanation:
1. These are intervals where the graph is above the x-axis, hence positive.
2. These are intervals where the graph is below the x-axis, hence negative.
3. The first interval is between the left peak and the valley, where the graph is decreasing. The second interval is right of the right peak, where the graph is also decreasing.
4. The first interval is left of the left peak, where the graph is increasing. The second interval is between the valley and the right peak, where the graph is also increasing.
