The following equations are solved in terms of x:
a) 2x - 3 = y
2x = y + 3
x = (1/2)y + 3/2
b) 2 + 2x - 1 = 4y
2x - 1 = 4y
2x = 4y + 1
x = 2y + 1/2
c) 2A + 4x + 3B = 10
4x = 10 - 2A - 3B
x = 5/2 - (1/2)A - (3/4)B
2x+2y=16
<span>2x+6y=28
all you have to do is subtract to get rid of the 2x and solve for y
2x+2y = 16
-2x-6y = -28
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0 -4y = -12
y = 3
now we got y we can plug in or do the systems of equation again and find x. lets do systems of equations again.
</span>2x+2y=16
<span>2x+6y=28
</span><span>
this time i am going to multiple the top by -3 and then add the equations hopefully it is clear why I multiple by -3
</span><span>
-3(2x+2y = 16)
2x +6y = 28
-6x - 6y = -48
</span>2x +6y = 28
------------------------
-4x + 0y = -20
x = 5
Answer:
The sum of coefficients = 9
Step-by-step explanation:
The given expression is,
3x⁴ + 5x² + x
There are three terms in the given expression. All the terms contains variable x.
<u>To find the coefficients of each terms
</u>
term coefficients
3x⁴ 3
5x² 5
x 1
<u>To find the sum of coefficients
</u>
sum = 3 + 5 + 1 = 9
Therefore the sum of coefficients = 9
Personally I think the answer would be c. Cross multiplication
