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blagie [28]
2 years ago
12

Find the LCM for the group of expressions. Y2+2y-24;y2-16;and 2y

Mathematics
1 answer:
sasho [114]2 years ago
3 0

Answer:

its here..........,,,

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  What values for θ (0 ≤ θ ≤ 2pie ) satisfy the equation? 
svetoff [14.1K]
Factor out the cos<span>θ:
</span>cosθ (2sin<span>θ + sqrt3) = 0
</span>Therefore, the only ways this can happen are if either cosθ = 0 or if (2sin<span>θ + sqrt3) = 0
</span>The first case, cosθ = 0 only at θ <span>= pi/2, 3pi/2.
</span>The second case, <span>(2sin<span>θ + sqrt3) = 0 simplifies to:
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Helga [31]
9/10....................................
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3 years ago
???????????????????????????????????????????
shusha [124]
For question 1, just plug in -2 as <em>h.

</em>-2(-2)^2-(-2)+2
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</em>You would get...

h(-2)=-4
<em>
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tensa zangetsu [6.8K]

That is your answer if it is wrong i will try to fix it

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