Answer:
x = ±4i or x = ±√-16
Step-by-step explanation:
x² - 5x + 19 = 5x + 3
x² + 16 = 0
x² = -16
x = ±√-16 (a negative square root is an imaginary number)
Answer:
10 friends
Step-by-step explanation:
we know that
The formula of the sum is equal to
![sum=\frac{n}{2}[2a1+(n-1)d]](https://tex.z-dn.net/?f=sum%3D%5Cfrac%7Bn%7D%7B2%7D%5B2a1%2B%28n-1%29d%5D)
where
a1 is the first term
n is the number of terms (number of friends)
d is the common difference in the arithmetic sequence
In this problem we have


----> the common difference
substitute in the formula and solve for n
![275=\frac{n}{2}[2(5)+(n-1)(5)]](https://tex.z-dn.net/?f=275%3D%5Cfrac%7Bn%7D%7B2%7D%5B2%285%29%2B%28n-1%29%285%29%5D)
![550=n[10+5n-5]\\ \\550=10n+5n^{2} -5n\\ \\5n^{2}+5n-550=0](https://tex.z-dn.net/?f=550%3Dn%5B10%2B5n-5%5D%5C%5C%20%5C%5C550%3D10n%2B5n%5E%7B2%7D%20-5n%5C%5C%20%5C%5C5n%5E%7B2%7D%2B5n-550%3D0)
Solve the quadratic equation by graphing
The solution is n=10
see the attached figure
therefore
She had 10 friends who got stickers
Answer:
Step-by-step explanation:
3,9,12,(15),16,18,21
mean (middle number) = 15
Q1 = 9.....the middle number of the numbers before the mean
Q3 = 18...the middle number of the numbers after the mean
interquartile range (IQR) = Q3 - Q1 = 18 - 9 = 9 <==
3y=4
4y=3
is that what you mean?