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BartSMP [9]
4 years ago
9

I need help with my homework please answer this correctly

Mathematics
1 answer:
masya89 [10]4 years ago
8 0

The correct answer is "3".

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Ur not telling us how to solve or what to solve.

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Algebra one quiz 12.2.3
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where is link

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3 years ago
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In circle O, ST is a diameter.
Andreas93 [3]

The value of x must be 25.0. The correct option is the second option-  25.0

<h3>Solving Linear equations </h3>

From the question, we are to determine the value of x

From the given diagram, we can write that

m ∠SOR + m ∠UOR + m ∠TOU = 180° (<em>Sum of angles on a straight line</em>)

∴ (2x +8)° + (3x - 14)° + (3x -14)° = 180°

2x° + 8° + 3x° -14° + 3x° -14° = 180°

Collect like terms

2x° + 3x° + 3x° + 8° - 14° -14° = 180°

8x° -20° = 180°

8x° = 180° + 20°

8x° = 200°

x = 200/8

x = 25.0

Hence, the value of x must be 25.0. The correct option is the second option-  25.0

Learn more Solving linear equations here: brainly.com/question/1413277

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2 years ago
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Question 2 is this a function? (2,4),(1,1),(0,0),(1,-1),(2,4)
Vadim26 [7]
No
there are multiple y values for 1 x(twice)
8 0
4 years ago
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Use inverse functions where needed to find all solutions of the equation in the interval 2 cos2 x + 9 sin x = 6
spin [16.1K]

You can use the identity \cos(2x) = \cos^2(x)-\sin^2(x) to write the equation as

2(\cos^2(x)-\sin^2(x))+ 9\sin(x) = 6

Now, from the fundamental equation of trigonometry, deduce an expression for \cos^2(x) in terms of \sin^2(x):

\cos^2(x)+\sin^2(x) = 1 \implies \cos^2(x) = 1-\sin^2(x)

The equation becomes

2(1-\sin^2(x)-\sin^2(x))+ 9\sin(x) = 6 \iff 2(1-2\sin^2(x))+ 9\sin(x) = 6

Simplify the left hand side and move all terms to left hand side:

2-4\sin^2(x)+ 9\sin(x) -6 = 0 \iff -4\sin^2(x) + 9\sin(x) - 4 = 0

Now, if you let t = \sin(x), this equation becomes a quadratic equation:

-4t^2 + 9t - 4 = 0

The two solutions of this equations are

t = \cfrac{9}{8} - \cfrac{\sqrt{17}}{8},\quad t = \cfrac{9}{8} + \cfrac{\sqrt{17}}{8}

We must be careful, because we have to remember that t was actually \sin(x). This means that t can only assume values between -1 and 1. The second solution exceeds 1, so we reject it. So, we have

t = \cfrac{9}{8} - \cfrac{\sqrt{17}}{8} \implies \sin(x) = \cfrac{9}{8} - \cfrac{\sqrt{17}}{8} \implies x = \arcsin\left(\cfrac{9}{8} - \cfrac{\sqrt{17}}{8}\right)

6 0
4 years ago
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