Answer:
The minimum power output used to accomplish this feat is 408.625 watts.
Step-by-step explanation:
The minimum power is that needed to overcome potential gravitational energy at constant velocity. From Principle of Energy Conservation, Work-Energy Theorem and definition of power we obtain the following relationship:
(Eq. 1)
Where:
- Mass of the athlete, measured in kilograms.
- Gravitational constant, measured in meters per square second.
- Climbing rate, measured in meters per second.
- Power, measured in watts.
By the consideration of constant velocity, we get that the climbing rate is represented by:
(Eq. 2)
Where:
- Travelled distance, measured in meters.
- Time, measured in seconds.
And by substituting on (Eq. 1), the following expression is found:

If we know that
,
,
and
, then the minimum power output is:


The minimum power output used to accomplish this feat is 408.625 watts.