A cannonball is shot straight up into the air. The height of the cannonball at time t is represented by the function f(t)=−16t^2
+40t+3 .
What does the 3 represent?
the initial velocity of the cannonball
the initial height of the cannonball
the time when the cannonball hits the ground
the maximum height of the cannonball
1 answer:
Answer:
the initial height
Step-by-step explanation:
given the height is represented by the function
f(t) = - 16t² + 40t + 3
Then the initial height is when t = 0, that is
f(0) = 0 + 0 + 3 = 3 ← initial height
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