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Oxana [17]
2 years ago
10

I need to solve for y in -19 = y + 6

Mathematics
2 answers:
olga2289 [7]2 years ago
8 0
Your answer is y=-25
Tju [1.3M]2 years ago
5 0

Answer:

y=-25

Step-by-step explanation:

-19=y+6

-6     -6

y=-25

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Find the volume of a regular hexahedron if one of the diagonals of its faces is 8 root 2 inches.
Naily [24]
The answer is 114sqrt{6} in³

A regular hexahedron is actually a cube. 

Diagonal of a cube D is a hypotenuse of a right triangle which other two legs are face diagonal (f) and length of a side (a):
D² = f² + a²

Face diagonal is a hypotenuse of a right triangle which sides are a and a:
f² = a² + a² =2a²

D² = f² + a²
f² = 2a²

D² = 2a² + a² = 3a²
D = √3a² = √3 * √a² = √3 * a = a√3

Volume of a cube with side a is: V = a³
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⇒ a = D/√3

V = a³ = (D/√3)³

We have:
D = 8√2 in

V= (\frac{D}{ \sqrt{3} } )^{3} =( \frac{8 \sqrt{2} }{ \sqrt{3} } )^{3}=( \frac{8 \sqrt{2} * \sqrt{3} }{ \sqrt{3}* \sqrt{3}} )^{3} =( \frac{8 \sqrt{2*3} }{ \sqrt{3*3}} )^{3} =( \frac{8 \sqrt{6} }{ \sqrt{3^{2} }} )^{3} =( \frac{8 \sqrt{6} }{ 3} )^{3} = \\ \\ = \frac{ 8^{3} *( \sqrt{6} )^{3}}{3^{3}} = \frac{512* \sqrt{6 ^{2} }* \sqrt{6} }{27} = \frac{512*6* \sqrt{6} }{27} = 114sqrt{6}
8 0
3 years ago
Will give correct answer brainliest
Sidana [21]
I’m pretty sure it’s x=10 because
8x + 50 = 130
So we would subtract 50 from both sides so it would be 8x = 130 - 50 then it would give us 80 so now we have 8x =80, now we will need to divide the 8 on both sides to get x, so 80/8 equals 10
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Answer:

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The answer is B, 25 inches.
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