Answer:
Step-by-step explanation:
These come directly from my textbook, so I'm not sure if your teacher will accept this kind of work.
1. Angle construction:
Given an angle. construct an angle congruent to the given angle.
Given: Angle ABC
Construct: An angle congruent to angle ABC
Procedure:
1. Draw a ray. Label it ray RY.
2. Using B as center and any radius, draw an arc that intersects ray BA and ray BC. Label the points of intersection D and E, respectively.
3. Using R as center and the same radius as in Step 2, draw an arc intersecting ray RY. Label the arc XS, with S being the point where the arc intersects ray RY.
4. Using S as center and a radius equal to DE, draw an arc that intersects arc XS at a point Q.
5. Draw ray RQ.
Justification (for congruence): If you draw line segment DE and line segment QS, triangle DBE is congruent to triangle QRS (SSS postulate) Then angle QRS is congruent to angle ABC.
You can probably also Google videos if it's hard to imagine this. Sorry, construction is super hard to describe.
Answer:
222 = score in 2nd game
Step-by-step explanation:
Let x = score in 1st game
3/4(x) + 30 = score in 2nd game
x + 3/4(x) + 30 = 478 Multiply thru by 4 to eliminate the fraction
4x + 3x + 120 = 1912
7x + 120 = 1912
7x = 1792
x = 256
3/4(x) + 30 = 3/4(256) + 30
= 192 + 30
222 = score in 2nd game
Check: 222 + 256 = 478
12.25x + 8.75y > = 90 (thats greater then or equal) <== ur inequality
Using pi at 3.14 the answer is 1,017.36
I’m pretty sure it’s the second answer? but not for sure i’ve done this before though
