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stiks02 [169]
3 years ago
10

If csc x = −5, find csc(−x) find the period and horizontal shift

Mathematics
1 answer:
ella [17]3 years ago
6 0

Answer:

\csc (-x) = - \csc x = - ( - 5) = 5

Period is 2π

Horizontal shift = 0

Step-by-step explanation:

We know that \sin (-x) = - \sin x and as \csc x = \frac{1}{\sin x}, so, we can write \csc (-x) = - \csc x

Therefore, the if \csc x = - 5 then \csc (-x) = - \csc x = - ( - 5) = 5 (Answer)

Now, the period of \csc x is 2π, hence the period of \csc (- x) is also 2π.  (Answer)

Again. \csc ( - x) = \csc (-x + 0), hence, the horizontal shift of \csc (- x) is 0. (Answer)

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3 years ago
Arelli uses 6.9 pints of white paint and blue paint to paint her bedroom walls. 3/4 of this amount is white paint, and the rest
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Answer:

1.73

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4 0
2 years ago
state whether the lines represented by the equations y=1/2x-1 and y+4=-1/2(x-2) are paraller, perdendicular, or neither
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The easiest way to tell whether lines are parallel, perpendicular, or neither is when they are written in slope-intercept form or y = mx + b. We will begin by putting both of our equations into this format.

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The second equation requires rearranging.
y + 4 =  -\frac{1}{2}(x - 2) \\ y + 4 = -\frac{1}{2}x + 1 \\ y = - \frac{1}{2} x- 3
From this equation, we can see that the slope is -1/2 and the y-intercept is -3.

When lines are parallel, they have the same slope. This is not the case with these lines because one has slope of 1/2 and the other has slope of -1/2. Since these are not the same our lines are not parallel.

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8 0
4 years ago
What is the value of n 9 x 23 +3 x39 - 28 = n
Flura [38]
Ok :) we should do according to order of operations
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction    (PEMDAS) 'it will be helpful for to remember '
 
anyways ;
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3×39=117 
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so now we will add and subtract= 207+117-28 =296
 
I HOPE IT WILL MAKE SENSE !!!!!!!



4 0
3 years ago
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