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aalyn [17]
4 years ago
10

What is equal to 0.25

Mathematics
1 answer:
Paha777 [63]4 years ago
8 0

Answer:

1/4

Step-by-step explanation:

0.25 means a quarter of a whole

Another way of saying a quarter is 1/4

It says that we need 1 part out of 4.

Therefore, 1/4 equals 0.25

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Serjik [45]
I would say either a or b

3 0
3 years ago
Find each value if f(x) = 2x - 1 and g(x) = 2 - x2.
bixtya [17]
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3 years ago
Which is the least positive integer that should be multiplied with 2 × 2 × 2 × 3 so that we get
Elan Coil [88]

Answer:

3

Step-by-step explanation:

In order to have a perfect square you have to have at least two prime factors, and since three is quite clearly not in a pair, the answer is three.

8 0
3 years ago
State whether the lines are parallel, perpendicular, coinciding, or neither: 6x+3y=–15 and y–3=–2x
lianna [129]

Answer:

Parallel

<u>Step-By-Step Explanation:</u>

Put the Function in Slope Intercept Form and Find the Slope of 6x+3y = 15

6x+3y = 15

3y = -6x + 15

3y/3 = -6x/3 + 15/3

y = -2x + 5

<u>We can see that the slope of 6x+3y = 15 is -2</u>

Put the Function in Slope Intercept Form and Find the Slope of y–3=–2x

y–3=–2x

y = -2x + 3

Here are our two Functions In Slope Intercept Form

y = -2x + 5

y = -2x + 3

<u>Remember the m = slope and the b = y-intercept</u>

y = mx + b

y = -2x + 5

y = -2x + 3

------------------------------------------------------------------------------------------------------

We can see both equations have the same slope of -2 so this means they could be parallel because parallel functions have the same slope but coinciding functions have the same slope too. To tell if the two functions are coinciding, the functions need to have the same slope and the same y-intercept. Looking at the two functions, we can see they have the same slope of -2 but their y-intercept are different so this makes the two functions parallel.

4 0
4 years ago
Let g(x)=2x and h(x)=x^2+4 find the value. (hog)(a)
lisov135 [29]
In short, (h o g)(a) is just h(    g(a)    ).

so what we can do is simply get g(a) first and then plug that in h(x).

\bf \begin{cases}&#10;g(x)&=2x\\&#10;h(x)&=x^2+4\\&#10;(h\circ g)(a)&=h(~~g(a)~~)&#10;\end{cases}&#10;\\\\\\&#10;g(a)=2(a)\implies g(a)=2a&#10;\\\\\\&#10;h(~~g(a)~~)\implies h(~~2a~~)=(2a)^2+4&#10;\\\\\\&#10;h(~~2a~~)=(2^2a^2)+4\implies  h(~~2a~~)=4a^2+4
8 0
4 years ago
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