Need help with #9 and #10

Pls help pls help pls help pls help pls help

Phoenix [80]

s=(2,4) r=(-3,1) the last point is=(2,1)

3 0

3 years ago

Please help me fill in da blanks to answer dis annoyin question

Trava [24]

Answer:

Step-by-step explanation:

b . v vvhc . fhd

5 0

4 years ago

If p(x) = 2x2 – 4x and q(x) = x – 3 what is (p*q)(x)

igomit [66]

The correct answer is 2x²-16x+30.

Explanation:
(p*q)(x) is a composition of the two functions p(x) and q(x); it is the same as p(q(x)). We replace every x in p(x) with our value of q(x), x-3:
instead of 2x², we have 2(x-3)², and instead of -4x, we have -4(x-3).

This gives us 2(x-3)²-4(x-3). This is the same as 2(x-3)(x-3)-4(x-3).

Multiplying, we have
2(x*x-3*x-3*x-3(-3))-(4*x-4*3)
=2(x²-3x-3x+9)-(4x-12)
=2(x²-6x+9)-4x+12.

Using the distributive property gives us
2*x²-2*6x+2*9-4x+12
=2x²-12x+19-4x+12.

Combine like terms, and we have 2x²-16x+30.

6 0

3 years ago

Read 2 more answers

Exercise 6

Lady_Fox [76]

$a)\\\\x^2-2x-4=0\\\\x^2-2x=4\\\\x^2-2x+1^2=4+1^2\\\\(x-1)^2=5\\\\x-1=\pm\sqrt5\\\\\underline{x=\pm\sqrt5+1\approx-1.24\ or\ 3.24}\\\\\\b)\\\\x^2-4x-2=0\\\\x^2-4x=2\\\\x^2-4x+2^2=2+2^2\\\\(x-2)^2=6\\\\x-2=\pm\sqrt6\\\\\underline{x=\pm\sqrt6+2\approx-0.45\ or\ 4.45}$

$c)\\\\x^2+8x+5=0\\\\x^2+8x=-5\\\\x^2+8x+4^2=-5+4^2\\\\(x+4)^2=11\\\\ x+4=\pm\sqrt{11}\\\\\underline{x=\pm\sqrt{11}-4\approx-7.32\ or\ -0.68}\\\\\\x)\\\\x^2+22x-15=0\\\\x^2+22x=15\\\\x^2+22x+11^2=15+11^2\\\\(x+11)^2=136\\\\x+11=\pm\sqrt{136}\\\\\underline{x=\pm\sqrt{136}-11\approx-22.66\ or\ 0.66}$

$e)\\\\x^2-7x+10=0\\\\x^2-7x=-10\\\\x^2-7x+(\frac72)^2=-10+(\frac72)^2\\\\x^2-7x+(\frac72)^2=-10+(\frac72)^2\\\\(x-\frac72)^2=-\frac{20}4+\frac{49}4\\\\ (x-\frac72)^2=\frac{29}4\\\\x-\frac72=\pm\sqrt{\frac{29}4}\\\\ \underline{x=\pm\frac{\sqrt{29}}2+\frac72\approx6.19\ or\ 0.81}\\\\\\f)\\\\x^2+5x-2=0\\\\x^2+5x=2\\\\x^2+5x+(\frac52)^2=2+(\frac52)^2\\\\(x+\frac52)^2=2+6.25 \\\\x+\frac52=\pm\sqrt{8.25}\\\\\underline{x=\pm\sqrt{8.25}-\frac52\approx-5.37\ or\ 0.37}$

$g)\\\\x^2+9x-4=0\\\\x^2+9x=4\\\\x^2+9x+(\frac92)^2=4+(\frac92)^2\\\\(x+\frac92)^2=4+20.25\\\\x+\frac92=\pm\sqrt{24.25}\\\\\underline{x=\pm\sqrt{24.25}-4.5\approx-9.42\ or\ 0.52}$

$h)\\\\x^2-3x-6=0\\\\x^2-3x=6\\\\x^2-3x+(\frac32)^2=6+(\frac32)^2\\\\(x-\frac32)&^2=6+2.25\\\\x-\frac32=\pm\sqrt{8.25}\\\\ \underline{x=\pm\sqrt{8.25}+1.5\approx4.37\ or-1.37}$

3 0

3 years ago

In ΔFGH, the measure of ∠H=90°, HF = 1.2 feet, and FG = 5.7 feet. Find the measure of ∠F to the nearest tenth of a degree.

amid [387]

Answer:

77.8

Step-by-step explanation:

don't ask

3 0

3 years ago