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EleoNora [17]
3 years ago
9

If p(x) = 2x2 – 4x and q(x) = x – 3 what is (p*q)(x)

Mathematics
2 answers:
igomit [66]3 years ago
6 0
<span>The correct answer is 2x</span>²<span>-16x+30.

Explanation<span>:
(p*q)(x) is a composition of the two functions p(x) and q(x); it is the same as p(q(x)). We replace every x in p(x) with our value of q(x), x-3:
instead of 2x</span></span>²<span><span>, we have 2(x-3)</span></span>²<span><span>, and instead of -4x, we have -4(x-3).

This gives us 2(x-3)</span></span>²<span><span>-4(x-3). This is the same as 2(x-3)(x-3)-4(x-3).

Multiplying, we have
2(x*x-3*x-3*x-3(-3))-(4*x-4*3)
=2(x</span></span>²<span><span>-3x-3x+9)-(4x-12)
=2(x</span></span>²<span><span>-6x+9)-4x+12.

Using the distributive property gives us
2*x</span></span>²<span><span>-2*6x+2*9-4x+12
=2x</span></span>²<span><span>-12x+19-4x+12.

Combine like terms, and we have 2x</span></span>²<span><span>-16x+30.</span></span>
DaniilM [7]3 years ago
4 0

Answer:

2x^2-16x+30

Step-by-step explanation:

Just took the quiz

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Simplify √ a^7 , where a&gt;0 Which expression is equivalent to √a^7
Softa [21]

Answer:

a^{3} \sqrt[]{a}

Step-by-step explanation:

8 0
3 years ago
Triangle ABC has verticals A (3,0),B (9,5)and (7,-8) find the length of AC in simplest radical form
AlladinOne [14]
length =  \sqrt{(0+8)^2 + (3-7)^2} =  \sqrt{64 + 16} =  \sqrt{80} = 4\sqrt{5}


Answer: Length = 4√5 units.
4 0
4 years ago
Rewrite the following polynomial in standard form
blagie [28]

Answer:

-7x³ - ⅑x - 1

Step-by-step explanation:

A polynomial written in standard form would be written in such a way that the term with the highest degree comes first, followed by the second highest and so on, then what comes last is the constant.

Given the polynomial -7x³ - 1 - ⅑x, -7x³ with the highest degree comes first, followed by -⅑x, and then the constant, -1, comes last.

Thus, we would have:

✅-7x³ - ⅑x - 1

8 0
3 years ago
Ten young adults living in California rated the taste of a newly developed sushi pizza topped with tuna, rice, and kelp on a sca
timurjin [86]

Answer: For California: μ = 33.1; σ² = 1120.50; Range = 32;

For Iowa: μ = 24.5; σ² = 32.73; Range = 19

Step-by-step explanation:

Mean is the average of a population or a sample. It is defined as

μ = ∑x / n, where

x is each number of the set;

n is the total individuals in the sample.

Calculating the <u>Mean</u> for sample of taste of pizza in <u>California</u>:

μ₁ = \frac{34+39+40+46+33+31+34+14+15+45}{10} = 33.1

Calculating the <u>Mean</u> for the sample in Iowa:

μ₂ = \frac{28+25+35+16+25+29+24+26+17+20}{10} = 24.5

Variance measures how far the number in the set is from the mean. Its formula is

σ² = (∑x-μ)² / n -1

which means to find the variance, you have to get the difference between the number and the mean, square the result, add all of them and then divide by (n-1) individuals.

The <u>Variance</u> for the sample in <u>California</u> is

σ² = \frac{(34 - 33.1)^{2}+(39-33.1)^{2}+(40-33.1)^{2}+(46-33.1)^{2}+(33-33.1)^{2}+(34-33.1)^{2}+(14-33.1)^{2}+(15-33.1)^{2}+(45-33.1)^{2}}{9}σ² = 120.50

The <u>Variance</u> for the sample in <u>Iowa</u> is

σ² = 32.73

Range is the difference between the highest and the lowest number of the set: range = highest - lowest

For the sample in <u>California</u>, the <u>Range</u> is

range = 46 - 14 = 32

For the sample in Iowa:

range = 35 - 16 = 19

For California:

  • Mean = 33.1;
  • Variance = 120.50;
  • Range = 32;

For Iowa:

  • Mean = 24.5;
  • Variance = 32.73;
  • Range = 19;

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6 0
3 years ago
Use properties of limits and algebraic methods to find the limit, if it exists. (If the limit is infinite, enter '[infinity]' or
soldi70 [24.7K]

Answer:

The limit of this function does not exist.

Step-by-step explanation:

\lim_{x \to 3} f(x)

f(x)=\left \{ {{9-3x} \quad if \>{x \>< \>3} \atop {x^{2}-x }\quad if \>{x\ \geq \>3 }} \right.

To find the limit of this function you always need to evaluate the one-sided limits. In mathematical language the limit exists if

\lim_{x \to a^{-}} f(x) = \lim_{x \to a^{+}} f(x) =L

and the limit does not exist if

\lim_{x \to a^{-}} f(x) \neq \lim_{x \to a^{+}} f(x)

Evaluate the one-sided limits.

The left-hand limit

\lim_{x \to 3^{-} } 9-3x= \lim_{x \to 3^{-} } 9-3*3=0

The right-hand limit

\lim_{x \to 3^{+} } x^{2} -x= \lim_{x \to 3^{+} } 3^{2}-3 =6

Because the limits are not the same the limit does not exist.

8 0
4 years ago
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