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3 years ago

Please help me fill in da blanks to answer dis annoyin question

Mathematics

1 answer:

Trava [24]3 years ago

5 0

Answer:

Step-by-step explanation:

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(05.01 MC) In triangle JKL, tan(b°) = three fourths and cos(b°) =four fifths. If triangle JKL is dilated by a scale factor of on

REY [17]

Answer:

$sin(b^\circ) = \dfrac{3}{5}$

Step-by-step explanation:

We are given a $\triangle JKL$ where $\angle K = 90^\circ$

$tan(b^\circ) = \dfrac{3}{4}\\cos(b^\circ) = \dfrac{4}{5}$

As per trigonometric rules,

$tan(\theta) = \dfrac{Perpendicular}{Base}$

$cos(\theta) = \dfrac{Base}{Hypotenuse}$

Comparing the given value of tangent and cosine:

Perpendicular = 3 units

Base = 4 units

Hypotenuse = 5 units

Also, we know that:

$sin(\theta) = \dfrac{Perpendicular}{Hypotenuse}$

$\Rightarrow sin(b^\circ) = \dfrac{3}{5}$

Now, it is given that the triangle is dilated by a scale factor of $\frac{1}{2}$ .

i.e. all the sides will become half of its initial values.

New Perpendicular = 1.5 units

New Base = 2 units

New Hypotenuse = 2.5 units

Using the formula for sine:

$sin(\theta) = \dfrac{Perpendicular}{Hypotenuse}$

$\Rightarrow sin(b^\circ)= \dfrac{1.5}{2.5}\\\Rightarrow sin(b^\circ)= \dfrac{15}{25}\\\Rightarrow sin(b^\circ)=\dfrac{3}{5}$

5 0

3 years ago

Consider this quadratic equation:

lara31 [8.8K]

A = 6
b = 9
c = -10
hope this helps you!

6 0

3 years ago

Persamaan suatu lingkaran adalah xpangkat2+ypangkat2+4x-6=0 tolong dong

snow_tiger [21]

That looks confusing can u explain better

8 0

3 years ago

18 is 0.75% of what number?

LUCKY_DIMON [66]

0.135 is your answer pretty sure.

4 0

3 years ago

What is 3x+2x(x-1)=9x+4

Korvikt [17]

3x+2(x-1)=9x=4
We move all terms to the left:
3x+2(x-1)-(9x)=0
We add all the numbers together, and all the variables
-6x+2(x-1)=0
We multiply parentheses
-6x+2x-2=0
We add all the numbers together, and all the variables
-4x-2=0
We move all terms containing x to the left, all other terms to the right
-4x=2
x=2/-4
x=-1/2

5 0

3 years ago