Y = x^2 + 2x - 1 = x^2 + 2x + 1 - 1 - 1 = (x + 1)^2 - 2
The vertex of a parabola given by y = a(x - h)^2 + k is (h, k).
Therefore, the vertex of y = (x + 1)^2 - 2 is (-1, -2)
And how would I do that via computer? If this is homework, do it your self, it's not that hard. Draw it and scan it (man computer doesn't have the ability to scan things)
Answer:
okay here goes.
Step-by-step explanation:
1. slope = -5 and y-intercept is (0,6)
2. slope = 3 and y-intercept is (0,-2)
3. -2 and (0,-4)
4. 8 and (0,1)
5. 5 and (0,-3)
6. -3 and (0,-9)
7. 7 and (0,2)
8. -1 and (0,6)
9. -4 and (0,7)
10. -6 and (0,-8)
11. 8 and (0,-5)
12. 9 and (0,3)
You owe me. That took a long time to write.
Answer:
<h2>6</h2>
Step-by-step explanation:
f(x)=-x+4
f(-2)=-(-2)+4
f(-2)=+2+4
f(-2)=6
