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babunello [35]
3 years ago
10

*HURRY PLEASE ANSWER* Richard is asked to spray wash the exterior of a building that is shaped like a cube. He decides to calcul

ate the surface area of the building in order to estimate how much water he will need. He does the calculation using the standard formula and, after doing the job, realizes he overestimated the amount of water he needed. Where was his mistake? a.) He forgot that there is no formula for the surface area of a cube. b.) He forgot to add the area of the base to the total surface are of the cube. c.) He forgot to square the result. d.) He forgot to subtract the area of the base from the total surface area of the cube.
Mathematics
2 answers:
Ludmilka [50]3 years ago
7 0

Answer:

D. He forgot to subtract the area of the base from the total surface area of the  cube.

Step-by-step explanation:

He is only spray washing the *exterior* of the building; the base is not exposed so it will not be spray washed, which means Richard can use less water.

Hope this helps. :)

Lelu [443]3 years ago
4 0

Answer:

D

Step-by-step explanation:

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(4x2 - 10x -24) (2x + 3)
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Answer:

Apply BODMAS

Step-by-step explanation:

PLEASE FIND THE PICTURE BELLOW

SOLUTION STEPS

(4⋅2−10x−24)(2x+3)

Multiply 4 and 2 to get 8.

(8−10x−24)(2x+3)

Subtract 24 from 8 to get −16.

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3 years ago
Which equation represents exponential decay?
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8 0
3 years ago
Read 2 more answers
Assume the acceleration of the object is a(t) = −32 feet per second per second. (Neglect air resistance.) A balloon, rising vert
Liula [17]

Answer:

(a) 2.79 seconds after its release the bag will strike the ground.

(b) At a velocity of 73.28 ft/second it will hit the ground.

Step-by-step explanation:

We are given that a balloon, rising vertically with a velocity of 16 feet per second, releases a sandbag at the instant when the balloon is 80 feet above the ground.

Assume the acceleration of the object is a(t) = −32 feet per second.

(a) For finding the time it will take the bag to strike the ground after its release, we will use the following formula;

                        s=ut+\frac{1}{2} at^{2}

Here, s = distance of the balloon above the ground = - 80 feet

          u = intital velocity = 16 feet per second

          a = acceleration of the object = -32 feet per second

          t = required time

So,  s=ut+\frac{1}{2} at^{2}

      -80=(16\times t)+(\frac{1}{2} \times -32 \times t^{2})

       -80=16t-16 t^{2}

       16 t^{2} -16t -80 =0

          t^{2} -t -5 =0

Now, we will use the quadratic D formula for finding the value of t, i.e;

           t = \frac{-b\pm \sqrt{D } }{2a}

Here, a = 1, b = -1, and c = -5

Also, D = b^{2} -4ac = (-1)^{2} -(4 \times 1 \times -5) = 21

So,  t = \frac{-(-1)\pm \sqrt{21 } }{2(1)}

      t = \frac{1\pm \sqrt{21 } }{2}

We will neglect the negative value of t as time can't be negative, so;

t = \frac{1+ \sqrt{21 } }{2} = 2.79 ≈ 3 seconds.

Hence, after 3 seconds of its release, the bag will strike the ground.

(b) For finding the velocity at which it hit the ground, we will use the formula;

                       v=u+at

Here, v = final velocity

So,  v=16+(-32 \times 2.79)

      v = 16 - 89.28 = -73.28 feet per second.

Hence, the bag will hit the ground at a velocity of -73.28 ft/second.

8 0
3 years ago
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elena-s [515]

Answer:A.) 1.554555

D.)1.554555 are irrational numbers.

Step-by-step explanation:

8 0
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