<h2><u>Part A:</u></h2>
Let's denote no of seats in first row with r1 , second row with r2.....and so on.
r1=5
Since next row will have 10 additional row each time when we move to next row,
So,
r2=5+10=15
r3=15+10=25
<u>Using the terms r1,r2 and r3 , we can find explicit formula</u>
r1=5=5+0=5+0×10=5+(1-1)×10
r2=15=5+10=5+(2-1)×10
r3=25=5+20=5+(3-1)×10
<u>So for nth row,</u>
rn=5+(n-1)×10
Since 5=r1 and 10=common difference (d)
rn=r1+(n-1)d
Since 'a' is a convention term for 1st term,
<h3>
<u>⇒</u><u>rn=a+(n-1)d</u></h3>
which is an explicit formula to find no of seats in any given row.
<h2><u>Part B:</u></h2>
Using above explicit formula, we can calculate no of seats in 7th row,
r7=5+(7-1)×10
r7=5+(7-1)×10 =5+6×10
r7=5+(7-1)×10 =5+6×10 =65
which is the no of seats in 7th row.
-3 and 3, both three away from 0
Answer:
Ummm... Jeez I don't know, this is hard.
Maybe pentagon?
(Thanks btw)
Answer:
They are 240 kilometers apart.
Step-by-step explanation:
This question can be solved using the following relation:
In which v is the velocity, d is the distance and t is the time.
An express train travels 80km/h from Ironton to Wildwood.
Here we have 
. So
A local train, traveling at 48km/h, takes 2 hours longer for the same trip.
This means that when ![v = 48, t = x + 2[tex]. So[tex]v = \frac{d}{t}](https://tex.z-dn.net/?f=v%20%3D%2048%2C%20t%20%3D%20x%20%2B%202%5Btex%5D.%20So%3C%2Fp%3E%3Cp%3E%5Btex%5Dv%20%3D%20%5Cfrac%7Bd%7D%7Bt%7D)
Since
Applying cross multiplication
So the distance is:
They are 240 kilometers apart.
Answer:
natural number
Step-by-step explanation:
natural number
