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LiRa [457]
3 years ago
11

Suppose Caryl could spend up to $30, what is another possible combinations of cupcakes and brownies that she could buy? How coul

d this change the system? Cupcakes is $3.50 and Brownies is $4.25
Mathematics
1 answer:
mezya [45]3 years ago
5 0
4 cupcakes and 4 brownies she can buy
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NEED ASAP How much wrapping paper is needed to wrap a box were all sides measure 5 inches ?
ollegr [7]

Answer: it depends on a wrapping paper

Step-by-step explanation:

5 0
3 years ago
4. Decide if the segment lengths form a triangle. If they do, Indicate whether the triangle is acute, right, or obtuse.
beks73 [17]
To see if line segments may form a triangle basically one must check if the sum of two sides are greater than the third. 
 a + b > c
a + c > b
b + c > a

a. can form a triangle
b. can form a triangle
c. can form a triangle
d. cannot form a triangle as 14 + 21 = 35 which is not greater than 36

a = right triangle with the right angle between 16 and 30
b = acute triangle
c = obtuse triangle with teh obtuse angle between 7 and 24
7 0
3 years ago
Find the value of x in the triangle. Round your answer to the nearest tenth of a degree. Show your work
Veseljchak [2.6K]
<h3>Solution:</h3>

\tan(x) = \frac{15}{8} \\ x = \arctan(\frac{15}{8}) \\ x ≈ 61.93

<h3>Answer:</h3>

61.93

5 0
3 years ago
what is the probability that s+d&gt;3 and s.d&gt;3? write your answer as a decimal rounded to hundreth place
maw [93]

The probability that s+d > 3 and sd > 3 is 0.03.

<h3>Solution</h3>

Plot the inequalities

The region -5 ≤ s,d ≤ 5 is the square shaded in grey.

The region s + d > 3 is the region Q shaded to the right of the straight line.

The region sd > 3 is the region R shaded to the right of the curve d = 3/s.

Find the intersection of the three regions

From the figure, the region satisfying all the above three inequalities is the region to the left of the curve d = 3/s, bounded by the square region, i.e. the region R.

Probability of region R

The required probability is the Geometric probability of the intersection region R. It is calculated as

P(R) = ar(region R) / ar(square region P).

Calculate the areas of the regions

ar(region R) = area of the rectangle to the right in the first quadrant formed by dropping a vertical from point F - area under the curve d = 3/s in the first quadrant

\[\Rightarrow \;\; \mathrm{ar(\mathbf{R}) =} \int_{3/5}^5\frac{3}{s}ds = 25-3-3\ln\frac{25}{3} = 15.64.\]

ar(region P) = 25 × 25 = 625.

Calculate P(R)

The probability of the region R, P(R) = 15.64 / 625 = 0.025.

Rounding it to the hundredth place of decimal, P(R) = 0.03.

The probability that s+d >3 and sd>3, where -5 < s,d < 5, is 0.03.

Learn more about the Probability here

brainly.com/question/13604758


Disclaimer: The question was incomplete. Please find the full content below.

<h3>Question</h3>

What is the probability that s + d > 3 and sd > 3, where -5 ≤ s,d ≤5? Write your answer as a decimal rounded to the hundredth place.

#SPJ10

8 0
2 years ago
Help pleaseeeeeeeeeeeeeeeeeee
klemol [59]

The first equation

6x^2 -18x-24=0

-the graph opens up

6(x^2 -3x -4)=0

6(x^2 -3x +9/4-4-9/4)=0

6(x-3/2)-25x6/4=

6(x-3/2)-75/2

-Vertex is at (3/2, -75/2)

-Axis of symmetry is x=3/2

Second equation

3r^2 -16r -12=0

-the graph opens up

...

7 0
3 years ago
Read 2 more answers
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