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inysia [295]
3 years ago
13

F(x) = −7x −1f( ??? ) = -8

Mathematics
1 answer:
Viefleur [7K]3 years ago
8 0

Answer:

f(1)

Step-by-step explanation:

f(x) = -7x -1

f(1) = -7×(1)-1

= -7-1 [- × - = +] and the sign is taken -ve bacause the higher value digit contain -ve sign

= -8

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Segment AB has point A located at (6, 6). If the distance from A to B is 5 units, which of the following is the coordinate for p
Ierofanga [76]
The choices are (3, 2) (2, 5) (6, 7) and (7, 5). The distance formula given two points is d = square root of [<span>(y2−y1)^2+(x2−x1)^2]. In this case, we try every point in the choices and substitute y1 equal to 6 and x1 equal to 6 as well.  The answer is A from the choices. 
</span>d=square root of [(6−2)^2+(6−3)2]
d=square root of [(4)^2+(3)^2] d=square root of [16+9] d=<span>square root of [</span>25]
d=5
4 0
4 years ago
Do not use your calculator for Parts 1 through 4.
Hunter-Best [27]
You have to understand how piecewise functions first
I hope you do because I won't be explaining it here



1.
if it is continiuous at x=1 then the part of the function that approaches 1 from the left is the same value
so we have f(x)=3-x for x<1, so evaluate it for x=1,
we would get 3-1=2
so
if a=2 and b=3

f(x)=2x²+3x
for x=1, we get 2+3=5

it approaches 2 from the left but equals 5
2≠5
so it is not continuous because it doesn't approach the same value at x=1




2.
alright
so we established that it should approach 2 because we had the f(x)=3-x
so
f(1)=2=ax²+bx
2=a+b
the relationship is 2=a+b



3.
same as before, but use the other function, the one that is defined at x≥2
5x-10, 5(2)-10, 10-10, 0
it approaches 0
so
we must find one such that f(x)=0 for x=2 with the ax²+bx
0=a(2)²+b(2)
0=4a+2b
if we minus 2b both sides
-2b=4a
divide by 2
-b=2a
add b both sides
0=2a+b



4.
2=a+b
0=2a+b

2=a+b
minus b both sides
2-b=a
subsitute
0=2a+b
0=2(2-b)+b
0=4-2b+b
0=4-b
b=4

sub back
2-b=a
2-4=a
-2=a

a=-2
b=4


5.
graph f(x)=-2x²+4x from x=1 to x=2 and put a closed dot at (1,2) and an open dot at (2,0)
4 0
3 years ago
ASAP!! WILL MARK BRAINLIEST!!Nelson cut a pizza into equal parts. 4 of the pieces were eaten. 2 pieces were left over, creating
goblinko [34]

Answer:

60 degrees

Step-by-step explanation:

angle 120 divided by two gives you 60 degrees or the angle of one slice

5 0
3 years ago
Read 2 more answers
A car travels 32 km due north and then 46 km in a direction 40° west of north. Find the direction of the car's resultant vector.
tatuchka [14]

Answer:

Step-by-step explanation:

This requires some serious work before we even begin. First off, we will convert the km to meters:

32 km = .032 m

46 km = .046 m

And then we have to deal with the angle given as 40 degrees west of north. An angle 40 degrees west of north "starts" at the north end of the compass and moves towards the west (towards the left in a counterclockwise manner) 40 degrees. That means that the angle that is made with the negative x axis is a 50 degree angle. BUT the way angles are measured in standard form are from the positive x-axis, therefore:

40 degrees west of north = 50 degrees with the negative x axis = 130 degrees with the positive x axis. 130 is the angle measure we use. Phew! Now we're ready to start. Adding vectors requires us to use the x and y components of vectors in order to add them.

A_x=.032cos90.0 so

A_x=0 (the 90 degrees comes from "due north")

B_x=.046cos130 so

B_x=-.030 and if we add those to get the x component of the resultant vector, C:

C_x=-.030   And onto the y components:

A_y=.032sin90.0 so

A_y=.032

B_y=.046sin130 so

B_y=.035 and if we add those together to get the y component of the resultant vector, C:

C_y=.067  Note that since C_x is negative and C_y is positive, the resultant angle (the direction) will put us into QII.

We find the magnitude of C:

C_{mag}=\sqrt{(-.030)^2+(.067)^2}

We will round this after we take the square root to the thousandths place.

C_{mag}=.073m and now for the angle:

\theta=tan^{-1}(\frac{.067}{-.030}) which gives us an angle measure of -67, but since we are in QII, we add 180 to that to get that, in sum:

The magnitude of the resultant vector is .073 m at 113°

6 0
3 years ago
Please help with 3 math questions ( 50 points )
Mariulka [41]

Answer:

Step-by-step explanation:

1. Reflection over the x-axis: (x, y) → (x, -y)

ΔABC with A(5, 1), B(-2, 6) C(-3, 4), after a reflection along the x-axis becomes A'(5, -1), B'(-2, -6) C'(-3, -4)

2. Counterclockwise rotation of 90° about the origin: (x, y) → (-y, x)

ΔXYZ with X(1, 2), Y(9, 7) Z(10, 1), after a counterclockwise rotation of 90° about the origin the coordinates are X'(-2,1) Y'(-7,9) Z'(-1,10)

3.

Parallelogram WXYZ with W(2, -3), X(-5, -1), Y(-1, 2), Z(6, 0), has the image after a translation of (x, y) → (x – 5, y + 2) as

W'(2-5, -3+2), X'(-5-5, -1+2), Y'(-1-5, 2+2), Z'(6-5, 0+2)

W'(-3, -1), X'(-10, 1), Y'(-6, 4), Z'(1, 2)

The coordinates of W'(-3, -1)

See Graphs...

7 0
3 years ago
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