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jekas [21]
2 years ago
10

Find the value of x. Round to the nearest tenth

Mathematics
1 answer:
alina1380 [7]2 years ago
4 0

Answer:

x=10.8

Step-by-step explanation:

the image is the working out. hope this helps.

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Y ≤ -2x + 4. What points satisfy the inequality?
MrRissso [65]
​Subtract 4 from both sides
y−4≤−2x

 Divide both sides by −2
-  y-4/2  ≥ x

 Switch sides
<span>x  ≤  −   y−4/2<span><span><span><span><span>​​</span></span></span>​​





HOPE THIS HELPS!!
</span></span></span>
6 0
3 years ago
1.) Find the value of the discriminant and the the number of real solutions of
ruslelena [56]
Hi there!

When we have an equation standard form...
a {x}^{2} + bx + c = 0
...the formula of the discriminant is
D = b^2 - 4ac

When
D > 0 we have two real solutions
D = 0 we have one real solutions
D < 0 we don't have real solutions

1.) Find the value of the discriminant and the the number of real solutions of
x^2-8x+7=0

Plug in the values from the equation into the formula of the discriminant

( - 8) {}^{2} - 4 \times 1 \times 7 = 64 - 28 = 36

D > 0 and therefore we have two real solutions.

2.) Find the value of the discriminant and the number of real solutions of
2x^2+4x+2=0

Again, plug in the values from the equation into the formula of the discriminant.

{4}^{2} - 4 \times 2 \times 2 = 16 - 16 = 0

D = 0 and therefore we have one real solution.

~ Hope this helps you.
4 0
3 years ago
Read 2 more answers
-2(-6x+3u-1) use the distributive property to remove parentheses
Nikitich [7]

the answer is 12x-6u+2 hope this helps

4 0
3 years ago
Read 2 more answers
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