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3 years ago

Evaluate: 24-(-18)/(-6)

Mathematics

1 answer:

iren2701 [21]3 years ago

4 0

Answer:

Step-by-step explanation:

24-(-18)/(-6)

= 24 - 3

= 21

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Select the type of equations A. Consistent B. Equivalent C. Inconsistent

Marina CMI [18]

Answer:

Step-by-step explanation:

Because the lines are not equal.

sorry if this is wrong I am not good at this but I will give you my best guess

4 0

3 years ago

Simplify the expression. 4y + 3( y+1) + 2 (x + 5)

Alik [6]

Answer:

4y + 5x + 13

Step-by-step explanation:

4y + 3(y + 1) + 2(x+5)

Distribute

4y + 3y + (3 x 1) + 2x + (2 x 5)

4y + 3y + 3 + 2x + 10

Combine like terms

4y + 5x + 13

5 0

3 years ago

450 high school freshmen were randomly selected for a national survey. Among survey participants, the mean grade-point average (

umka21 [38]

Answer:

The margin of error is of 0.01.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.7}{2} = 0.15$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.15 = 0.85$ , so Z = 1.037.

The margin of error is of:

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

Standard deviation was 0.21.

This means that $\sigma = 0.21$

Sample of 450:

This means that $n = 450$

What is the margin of error, assuming a 70% confidence level, to the nearest hundredth?

$M = z\frac{\sigma}{\sqrt{n}}$

$M = 1.037\frac{0.21}{\sqrt{450}}$

$M = 0.01$

The margin of error is of 0.01.

4 0

3 years ago

1) A school has 1600 students and they are going to vote as to whether they will completely convert the school completely off fo

fredd [130]

Answer:

Standard deviation of the students = 0.408

The students would you have to poll to be 95% confident of the outcome within /- 2% of the vote

= 0.408 X 1600

= 652.8

Step-by-step explanation:

Step(i):-

Given sample size 'n' = 1600

95% confidence interval of the margin error is determined by

$M.E = \frac{Z_{0.05} S.D}{\sqrt{n} }$

Level of significance = 0.05

Z₀.₀₅ = 1.96

Given Margin of error = 2% = 0.02

$M.E = \frac{Z_{0.05} S.D}{\sqrt{n} }$

$0.02 = \frac{1.96 X S.D}{\sqrt{1600} }$

0.02 X √1600 = 1.96 X S.D

$S.D = \frac{0.02X\sqrt{1600} }{1.96} = 0.408$

Standard deviation of the students = 0.408

The students would you have to poll to be 95% confident of the outcome within /- 2% of the vote

= 0.408 X 1600

= 652.8

5 0

3 years ago

The teacher never taught this please help it’s for a grade

34kurt

Answer: D 2/3

Step-by-step explanation:

8 0

3 years ago