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Travka [436]
2 years ago
9

The second term of arithematic proggresions 7. and the sum of the first four termd is 12 find

Mathematics
1 answer:
Elza [17]2 years ago
3 0

Answer:

a) a1=15 first term

b) d=-8 common difference

Step-by-step explanation:

1)a1+d=7

2)a1+a2+a3+a4=12

a1+a1+d+a1+2d+a1+3d=12

4a1+6d=12

2a1+3d=6

We have the system of equations where a1+d=7 and 2a1+3d=6

3a1+3d=21

2a1+3d=6

Subtract the second equation from the first one

a1=15

d=-8

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Evaluate the expression when z=7 3z+8
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Point S is on line segment RT. Given RS = 4x – 10, ST = 2x – 10, and
borishaifa [10]

Answer:

The numerical length of RS is 22 units

Step-by-step explanation:

∵ Point S is on the line segment RT

→ <em>That means S divide RT into two parts RS and ST</em>

∴ RS + ST = RT

∵ RS = 4x - 10

∵ ST = 2x - 10

∵ RT = 4x - 4

→ <em>Substitute them in the statement above</em>

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→ <em>Divide both sides by 2 to find x</em>

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→ <em>Substitute the value of x in Rs to find its length</em>

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The numerical length of RS is 22 units

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