Answer:
(6,1)
Step-by-step explanation:
1.) group the x and y terms (and move the constant to the other side)
x²-12x+y²-2y= -12
divide the coeficcents for the terms with just 1 or 1 x variable by 2 and then square it (and add that to both sides)
x²-12x+36+y²-2y+1= -12+36+1
factor
(x-6)²+(y-1)²= 25
the center is therefore (6,1)
Answer:
Step-by-step explanation:
I think it is A
<span>To be both complex and imaginary, the answer would have to include "i" as well as have the form "a + bi". The first example, 3i - 5, fits. This would look to be the only example that does fit. The negative square root of 14 would be imaginary, but not complex.</span>
The slope of the first equation would be -5/2 because
2y=-5x+8
y=-5x/2+4
The y intercept of the 2nd equation is when x=0, so -7y=10
y=-10/7
The equation of the line would be y=-5x/2-10/7
Or in standard form....
5x/2+y=-10/7
5x+27=-20/7
Answer:
The perimeter is 43.6 cm
Step-by-step explanation:
In this question, we are tasked with calculating the perimeter of the sector.
Firstly, we define what a sector is. A sector is part of a circle which is is blinded by two radii and an arc. Hence we say a sector contains two radii.
Thus, to calculate the perimeter of the sector, we need the length of the arc added to 2 * length of the radius
Let’s calculate the length of the arc.
Mathematically, this is theta/360 * 2 * pi * r
where theta is the angle subtended at the middle of the circle which is 135 according to the question, and our radius is 10cm
Thus, we have
135/360 * 2 * 22/7 * 10 = 23.57 cm
Adding two radii to this, we have;
23.57 + 2(10)
= 23.57 + 20 = 43.57 = 43.6 cm to 1 decimal place
