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IRINA_888 [86]
2 years ago
8

Solve 8x + c = k for x.

Mathematics
2 answers:
Scrat [10]2 years ago
6 0

Answer:

x = \frac{k -c}{8}

Step-by-step explanation:

8x + c = k\\\\8x + c-c = k -c \ \ \ \ \ \ \ \ \ [\ subtract \ c \ from \ both \ sides \ ]\\\\8x = k - c\\\\\frac{8x}{8} = \frac{k-c}{8} \ \ \ \ \ [ \ divide \ both \ sides\  by\  8 \ ]\\\\x = \frac{k-c}{8}

tino4ka555 [31]2 years ago
5 0

Answer:

x = (k - c)/8

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Algebra I</u>

  • Terms/Coefficients

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

8x + c = k

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. [Subtraction Property of Equality] Subtract <em>c</em> on both sides:                         8x = k - c
  2. [Division Property of Equality] Divide 8 on both sides:                                 x = (k - c)/8
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An experimental population of fruit flies increases according to the law of exponential growth. There were 60 flies after the 2n
Mice21 [21]

Answer:

There were 10 flies originally

Step-by-step explanation:

Since we have an exponential growth, we will be having a constant percentage of increase and we can set up the increase at any day using the following equation;

V = I(1+r)^d

where V is the number of flies on a particular day

I is the initial number of flies

r is the constant increase in percentage

and d is the number of days.

So we have for the second day;

60 = I(1+r)^2 ••••••(i)

For the fourth day, we have;

360 = I(1+r)^4 ••••••••(ii)

divide equation ii by i; we have;

360/60 = (1+r)^4/(1+r)^2

6 = (1+r)^2

(√6)^2 = (1+r)^2

1 + r = √6

r = √6 - 1

So we can substitute the value of r in any of the equations to get I which is the initial number of flies

Let’s use equation 1

60 = I(1 + r)^2

60 = I(1 + √6 -1)^2

60 = I(√6)^2

60 = 6I

I = 60/6

I = 10 flies

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Oduvanchick [21]
404 error: graph not found

anyway, the graph was not included. since the sleep time was included, I will assume that the circle graph is worth 24 hours

all we need to do is to convert the percentages to fractions and multiply that by 24 to find out how many hours per activity


percent means parts out of 100 so x%=x/100


so we have
School
Eating
Sleep
Homework
Free Time

School=25%
25%=25/100=1/4
1/4 times 24=6
School: 6 hours


Eating=10%
10%=10/100=1/10
1/10 times 24=2.4
Eating: 2.4 hours


Sleep=40%
40%=40/100=4/10=2/5
2/5 times 24=48/5=9.6
Sleep: 9.6 hours


Homework=10%
10%=10/100=1/10
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Homework: 2.4 hours


Free Time=15%
15%=15/100=3/30
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Free Time: 3.6 Hours

Answers:
School: 6 hours
Eating: 2.4 hours
Sleep: 9.6 hours
Homework: 2.4 hours
Free Time: 3.6 Hours


3 0
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