Answer:
Written in Python
import math
principal = 8000
rate = 0.025
for i in range(1, 11):
amount = principal + principal * rate
principal = amount
print("Year "+str(i)+": "+str(round(amount,2)))
Explanation:
This line imports math library
import math
This line initializes principal amount to 8000
principal = 8000
This line initializes rate to 0.025
rate = 0.025
The following is an iteration from year 1 to 10
for i in range(1, 11):
This calculates the amount at the end of the year
amount = principal + principal * rate
This calculates the amount at the beginning of the next year
principal = amount
This prints the calculated amount
print("Year "+str(i)+": "+str(round(amount,2)))
It's GigaBytes actually. And is it RAM or storage capabilities?
And also those are brands. Not models. For example, Samsung has different phones. Not just one.
<span>Not a valid IPv6 address
A valid IPv6 address consist of 8 groups of 4 hexadecimal numbers separated by colons ":". But that can make for a rather long address of 39 characters. So you're allowed to abbreviate an IPv6 address by getting rid of superfluous zeros. The superfluous zeros are leading zeros in each group of 4 digits, but you have to leave at least one digit in each group. The final elimination of 1 or more groups of all zeros is to use a double colon "::" to replace one or more groups of all zeros. But you can only do that once. Otherwise, it results in an ambiguous IP address. For the example of 2001:1d5::30a::1, there are two such omissions, meaning that the address can be any of
2001:1d5:0:30a:0:0:0:1
2001:1d5:0:0:30a:0:0:1
2001:1d5:0:0:0:30a:0:1
And since you can't determine which it is, it's not a valid IP address.</span>
Storing memory maybe hope thishelped
number = 547
nums = {1:"one", 2:"two",3:"three",4:"four",5:"five",6:"six",7:"seven",8:"eight",9:"nine"}
print("The last digit of",number,"is",nums[number%10])
I wrote my code in python 3.8. I hope this helps.
