I think Its 6.............
For this, we use simultaneous equations. Let George's page be g, Charlie's be c and Bill's page be b.
First, <span>George's page contains twice as many type words as Bill's.
Thus, g = 2b.
</span><span>Second, Bill's page contains 50 fewer words than Charlie's page.
Thus, b = c - 50.
</span>If each person can type 60 words per minute, after one minute (i.e. when 60 more words have been typed) <span>the difference between twice the number of words on bills page and the number of words on Charlie's page is 210.
We can express that as 2b - c = 210.
Now we need to find b, since it represents Bill's page.
We can substitute b for (c - 50) since b = c - 50, into the equation 2b - c = 210. This makes it 2(c - 50) - c = 210.
We can expand this to 2c - 100 - c = 210.
We can simplify this to c - 100 = 210.
Add 100 to both sides.
c - 100 + 100 = 210 + 100
Then simplify: c = 210 + 100 = 310.
Now that we know c, we can use the first equation to find b.
b = c - 50 = 310 - 50 = 260.
260 is your answer. I don't know where George comes into it. Maybe it's a red herring!</span>
Answer: 12 tables minimum, 15 max.
Step-by-step explanation:
If you substitute 14 in an inequality
200c + 500t >= 8800
200(14) + 500t and solve for t, you get t must be at least 12.
C +T cannot exceed 29
So figure 14 +12 =26 so they could sell up to 15 tables and not go over 29.
You will have to enter the t values 12,13,14,15
1981+25
Since she was born in the year 1981, and her son was born 25 years later so you add 25
Hello,
h(x)= if x<3 then x+2
else -x+8
(–∞5[ U [5 –∞)=(–∞ 5]
Answer B