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3 years ago

Which ordered pairs in the form (x, y) are solutions to the equation

Mathematics

2 answers:

Xelga [282]3 years ago

5 0

1
4
Im sure ..................

inna [77]3 years ago

4 0

Answer:

(-1, 7) and (-6, -14) are solutions

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2 years ago

Find the exact values of a) sec of theta b)tan of theta if cos of theta= -4/5 and sin<0

Gre4nikov [31]

Answer:

Using trigonometric ratio:

$\sec \theta = \frac{1}{\cos \theta}$

$\tan \theta = \frac{\sin \theta}{\cos \theta}$

From the given statement:

$\cos \theta = -\frac{4}{5}$ and sin < 0

⇒ $\theta$ lies in the 3rd quadrant.

then;

$\sec \theta = \frac{1}{-\frac{4}{5}} = -\frac{5}{4}$

Using trigonometry identities:

$\sin \theta = \pm \sqrt{1-\cos^2 \theta}$

Substitute the given values we have;

$\sin \theta = \pm\sqrt{1-(\frac{-4}{5})^2 } =\pm\sqrt{1-\frac{16}{25}} =\pm\sqrt{\frac{25-16}{25}} =\pm \sqrt{\frac{9}{25} } = \pm\frac{3}{5}$

Since, sin < 0

⇒ $\sin \theta = -\frac{3}{5}$

now, find $\tan \theta$ :

$\tan \theta = \frac{\sin \theta}{\cos \theta}$

Substitute the given values we have;

$\tan \theta = \frac{-\frac{3}{5} }{-\frac{4}{5} } = \frac{3}{5}\times \frac{5}{4} = \frac{3}{4}$

Therefore, the exact value of:

(a)

$\sec \theta =-\frac{5}{4}$

(b)

$\tan \theta= \frac{3}{4}$

7 0

4 years ago

Some one please help me out on number 2? Please please.

Nataliya [291]

I'm not pretty sure but I think it would be y I'm not pretty good with these type of question so don't take my answer correctly but at least we tried I tried like 3 times and I guess I didn't really get it its very confusing but just refer to me as a stand off I'm pushing you to get it right good luck try answering my question on my page please I need to complete it tonight to get extra credit and I'm having a hard time that's why I signed up for brainly,com free for 30 days for my trial. Thank you very much

4 0

4 years ago

Read 2 more answers

Can someone pls help me?

nignag [31]

Step-by-step explanation:

ofc , so that is that and the other is that

4 0

3 years ago