2 years ago

Given AB= DE <A=<D and AC= DF

Mathematics

1 answer:

Vladimir79 [104]2 years ago

3 0

Answer:

Step-by-step explanation:

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Write the quadratic function in standard form.<br> f(x) = -x2 + 2x + 4<br> f(x) =

goldenfox [79]

Answer:

$f(x)=-1(x-2)^2+8$

Step-by-step explanation:

Given:

The quadratic function is given as:

$f(x)=-x^2+2x+4$

The standard form of a quadratic function is given as:

$f(x)=a(x-h)^2+k$ , where, 'a', 'h' and 'k' are real numbers.

Now, in order to convert the given function to standard form, we use completing by square method.

$-x^2+2x=-(x^2-2x)=-[(x-2)^2-2^2]=-[(x-2)^2-4]=-(x-2)^2+4$

Now, $f(x)=-x^2+2x+4$ can be rewritten as:

$f(x)=-(x-2)^2+4+4\\f(x)=-1(x-2)^2+8$

Therefore, the standard form of the function is:

$f(x)=-1(x-2)^2+8$

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2 years ago

Explain how you would factor 9x^2 – 49 show your work and use complete sentences. what is this special type of factoring called?

tatuchka [14]

9x² - 49

(3x)² - (7)²

= (3x + 7)(3x - 7)

This type of factoring is called Difference of Two Squares

where x² - y² = (x + y)(x - y)

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2 years ago

Given AB= DE <A=<D and AC= DF​

Given AB= DE <A=<D and AC= DF