Write an absolute value inequality with a solid boundary that only has solutions below the x-axis

Complete the identity.<br> 1) sec^4 x + sec^2 x tan^2 x - 2 tan^4 x = ?

Alecsey [184]

Answer:

See Explanation

Step-by-step explanation:

<em>Question like this are better answered if there are list of options; However, I'll simplify as far as the expression can be simplified</em>

Given

$sec^4 x + sec^2 x tan^2 x - 2 tan^4 x$

Required

Simplify

$(sec^2 x)^2 + sec^2 x tan^2 x - 2 (tan^2 x)^2$

Represent $sec^2x$ with a

Represent $tan^2x$ with b

The expression becomes

$a^2 + ab- 2 b^2$

Factorize

$a^2 + 2ab -ab- 2 b^2$

$a(a + 2b) -b(a+ 2 b)$

$(a -b) (a+ 2 b)$

Recall that

$a = sec^2x$

$b = tan^2x$

The expression $(a -b) (a+ 2 b)$ becomes

$(sec^2x -tan^2x) (sec^2x+ 2 tan^2x)$

..............................................................................................................................

In trigonometry

$sec^2x =1 +tan^2x$

Subtract $tan^2x$ from both sides

$sec^2x - tan^2x =1 +tan^2x - tan^2x$

$sec^2x - tan^2x =1$

..............................................................................................................................

Substitute 1 for $sec^2x - tan^2x$ in $(sec^2x -tan^2x) (sec^2x+ 2 tan^2x)$

$(1) (sec^2x+ 2 tan^2x)$

Open Bracket

$sec^2x+ 2 tan^2x$ ------------------This is an equivalence

$(secx)^2+ 2 (tanx)^2$

Solving further;

................................................................................................................................

In trigonometry

$secx = \frac{1}{cosx}$

$tanx = \frac{sinx}{cosx}$

Substitute the expressions for secx and tanx

................................................................................................................................

$(secx)^2+ 2 (tanx)^2$ becomes

$(\frac{1}{cosx})^2+ 2 (\frac{sinx}{cosx})^2$

Open bracket

$\frac{1}{cos^2x}+ 2 (\frac{sin^2x}{cos^2x})$

$\frac{1}{cos^2x}+ \frac{2sin^2x}{cos^2x}$

Add Fraction

$\frac{1 + 2sin^2x}{cos^2x}$ ------------------------ This is another equivalence

................................................................................................................................

In trigonometry

$sin^2x + cos^2x= 1$

Make $sin^2x$ the subject of formula

$sin^2x= 1 - cos^2x$

................................................................................................................................

Substitute the expressions for $1 - cos^2x$ for $sin^2x$

$\frac{1 + 2(1 - cos^2x)}{cos^2x}$

Open bracket

$\frac{1 + 2 - 2cos^2x}{cos^2x}$

$\frac{3 - 2cos^2x}{cos^2x}$ ---------------------- This is another equivalence

8 0

3 years ago

PLEASE PLEASE PLEASE HELP ME WITH THIS PROBLEM, IT"S 15 POINTS OUT OF 30!!!

koban [17]

Answer:

Do you solve it or drag the boxes?

Step-by-step explanation:

4 0

3 years ago

Please answer this correctly without making mistakes

Gekata [30.6K]

Answer:

16

Step-by-step explanation:

The distance is given by

d = sqrt( (x2-x1) ^2 + ( y2-y1) ^2)

Since the x values are the same

d = sqrt( ( y2-y1) ^2)

d = sqrt( (( -6 - 10)^2))

d = sqrt((-16) ^2)

d = 16

We can also just find the number of squares between the points since the x value is the same.

10 - -6

10+6

16

4 0

2 years ago

Read 2 more answers

I just need help to solve these steps.

My name is Ann [436]

I dont think the answer is 129 unless you typed the problem in wrong. Order of operations say to do everything inside the perenthesis first so you would do the 3*2 which is 6 then divide the 12 by 6 and you get 2. so your new equation is 8^2+9(2)-7. Next distribute the 9 to the 2 that is inside the perenthesis. Square root the 8 also. Now it is 49+18-7. The answer would be 60 ...?

6 0

2 years ago

A worker carries jugs of liquid soap from a production line to a packing area, carrying 4 jugs per trip. If the jugs are packed

Allisa [31]

Answer:

B. 2

Step-by-step explanation:

We have been given that a worker carries jugs of liquid soap from a production line to a packing area, carrying 4 jugs per trip.

Since worker has made 17 trips, so total number of hugs of liquid soap would be 17 times number of jugs carried per trip.

$17\times 4=68$ .

Since each carton holds 7 jugs, so number of cartoons would be $\frac{68}{7}$ .

$\frac{68}{7}\Rightarrow \frac{63+5}{7}=9\frac{5}{7}$

We can see that there are 9 completely filled cartoons and there are 5 jugs remaining, so we need $7-5=2$ jugs.

Therefore, we need 2 jugs to fill the 10th cartoon and option B is the correct choice.

7 0

2 years ago