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san4es73 [151]
3 years ago
15

Which property justifies this statement? If x=3, then x−3=0. Subtraction Property of Equality Division Property of Equality Refl

exive Property of Equality Multiplication Property of Equality
Mathematics
1 answer:
IgorLugansk [536]3 years ago
7 0

Answer:

Subtraction Property of Equality Division

Hope this helps (Just took the test btw)

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Answer:

1. 16

2. 8

3. 4

Step-by-step explanation:

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How to regroup 5 4/6
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5+4/6
Result: 17/3

OR

5+1/2+1/6
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3 years ago
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What is the scale factor in the dilation if the coordinates of A prime are (–7, 6) and the coordinates of C prime are (–4, 3)?
olchik [2.2K]

Option A: \frac{1}{3} is the dilation factor

Explanation:

The Coordinates of the square ABCD are A(-21,18), B(-12,18), C(-12,9), D(-21,9)

Also, the coordinates of the square A'B'C'D' are A'(–7, 6), B'(-4,6), C'(-4,3), D'(-8,3)

Now, we shall determine the scale factor in the dilation if the coordinates A' and C'.

Since, the dilation is the enlargement of the image in the same shape but different size.

To determine the scale factor, let us divide A'C' by AC

Thus, we have,

\begin{aligned}A^{\prime} C^{\prime} &=\sqrt{(-4+7)^{2}+(3-6)^{2}} \\&=\sqrt{3^{2}+(-3)^{2}} \\&=\sqrt{9+9} \\&=\sqrt{18}\\&=3\sqrt{2} \end{aligned}

Also,

\begin{aligned}A C &=\sqrt{(-12+21)^{2}+(9-18)^{2}} \\&=\sqrt{9^{2}+(-9)^{2}} \\&=\sqrt{81+81} \\&=\sqrt{162}\\&=9\sqrt{2} \end{aligned}

Dividing A'C' by AC, we have,

\frac{A'C'}{AC} =\frac{3\sqrt{2} }{9\sqrt{2}} =\frac{1}{3}

Thus, \frac{1}{3} is the dilation factor

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3 years ago
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The slope of the line is 4/3
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Which expression is equivalent to
mojhsa [17]

First choice: m^32n^16

Hope this helps!

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3 years ago
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