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Ghella [55]
3 years ago
5

Blake took out a 20-year loan for $195,000 at 2.4% interest, compounded

Mathematics
2 answers:
Leviafan [203]3 years ago
8 0

Answer:

C

Step-by-step explanation:

apex

jeka57 [31]3 years ago
6 0

Answer:  C. $633.84

Step-by-step explanation:

The formula to solve this problem is shown below

monthly payment on the loan is $1023.84

i = 2.4% interest

= loan * interest period - monthly payment on the loan

= $195,000 *(2.4/100 /120) - $1023.84 = $195,000*(0.024/12) - $1023.84

= $633.84

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and then
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If you'll do that, the solution will be right there on the paper in front of you.
It'll begin with "x =", and right after that will be the value of 'x'.


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3 years ago
To make a cake, you need 2 parts flour, 2 parts sugar and 1 part eggs.
Allisa [31]

Answer:

2:1???

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2 years ago
In a circle, area and circumference can be found using the formulas A=(pi)r^2 and C=2(pi)r, respectively, Write a formula for A
AURORKA [14]

Answer:

A = \dfrac{C^2}{4\pi}

Step-by-step explanation:

Given that

Area of a circle A=\pi r^2

Circumference of the circle C = 2 \pi r

Let us re-write the equation of area of circle:

A=\pi r^2

A = \pi \times r \times r

Multiplying and dividing with 2:

A = \dfrac{2\pi r}{2} \times r\\\text{Putting }2\pi r = C:\\\Rightarrow A = \dfrac{C}{2} \times r\\\text{Multiplying and dividing by } 2\pi:\\\Rightarrow A = \dfrac{C}{2} \times \dfrac{2\pi r}{2\pi}\\\text{Putting }2\pi r = C:\\\Rightarrow A = \dfrac{C \times C}{4 \pi}\\\Rightarrow A = \dfrac{C^2}{4 \pi}

Hence, <em>A</em> in terms of <em>C</em> can be represented as:

A = \dfrac{C^2}{4\pi}

4 0
4 years ago
a car purchased for $34,000 is expected to lose value, or depreciate, at a rate of 6% per year.using x for years and y for the v
Vika [28.1K]

Answer:

y = 34000(1-0.06) ^ t

After 7.40 years it will be worth less than 21500

Step-by-step explanation:

This problem is solved using a compound interest function.

This function has the following formula:

y = P(1-n) ^ t

Where:

P is the initial price = $ 34,000

n is the depreciation rate = 0.06

t is the elapsed time

The equation that models this situation is:

y = 34000(1-0.06) ^ t

Now we want to know after how many years the car is worth less than $ 21500.

Then we do y = $ 21,500. and we clear t.

21500 = 34000(1-0.06) ^ t\\\\log(21500/34000) = tlog(1-0.06)\\\\t = \frac{log(21500/34000)}{log(1-0.06)}\\\\t = 7.40\ years.

After 7.40 years it will be worth less than 21500

3 0
3 years ago
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