What are 2 equivalent rations to 4:3

The time that passes between the time you see lightning and you hear the thunder depends on your distance from the lightning. Wi

xxTIMURxx [149]

When the lightning occurs 4.5 km away then we will hear after 13.5 seconds and if we hear after 1.5 seconds then we are 0.5 km away from lightning.

Given With each km from the lightning 3 seconds passes.

a) The table of values for distances from 0 to 5 km.

Distances Time

0 0

1 3

2 6

3 9

4 12

5 15

b) The graph of lightning is a linear relation because it is increasing constantly by 3 seconds. f(x)=3x

c) When distance =1 , the time be 3 seconds

when distance =4.5 , the time=3*4.5

=13.5 seconds.

d) When time is 3 seconds = 1km

when time =1.5 seconds , the distance be 1/2=0.5 km.

Learn more about graph at brainly.com/question/4025726

#SPJ10

5 0

2 years ago

A rectangle is 5.1 cm wide and each diagonal is 9.3 cm long. What is the measure of the angle between a diagonal and the shorter

Anastasy [175]

Answer:

56.7°

Step-by-step explanation:

A rectangle is 5.1 cm wide and each diagonal is 9.3 cm long. What is the measure of the angle between a diagonal and the shorter side of the rectangle to the nearest tenth of a degree?

We solve this question using the Trigonometric function of Sine

From the question, we are told that:

A rectangle is 5.1 cm wide

and each diagonal is 9.3 cm long.

Since we have a diagonal, this means the shape is transformed to a triangle.

The width of the rectangle = Adjacent side of a triangle = 5.1cm

The diagonal of the rectangle = Hypotenuse = 9.3cm

Hence,

cosθ = Adjacent/Hypotenuse

cosθ = 5.1/9.3

cosθ = 0.5483870968

θ = arccos(0.5483870968)

θ = 56.743568714°

Approximately = 56.7°

The measure of the angle is 56.7°

3 0

3 years ago

What is the center of a circle (x, y) with the equation (x + 3)2 + (y – 5)2 - 16?

stepan [7]

Answer:

A: (3,5)

Step-by-step explanation:

Hopefully this helps

3 0

3 years ago

Can someone please help me please?

Oksi-84 [34.3K]

Answer: It is B

5x-3/x-1

4 0

3 years ago

A jar contains 12 red marbles numbered 1 to 12 and 6 blue marbles numbered 1 to 6. A marble is drawn at random from the jar. Fin

lora16 [44]

Answer:

$(a)P(Red)=\dfrac{2}{3}\\(b)P(Odd) =\dfrac{1}{2}\\(c)P(\text{Red or Odd Numbered})=\dfrac{5}{6}\\(d)P(\text{Blue or Even Numbered})=\dfrac{2}{3}$

Step-by-step explanation:

Number of Red Marbles{1,2,3,4,5,6,7,8,9,10,11,12},n(R)=12

Number of Blue Marbles{1,2,3,4,5,6},n(B)=6

Total Number of Marbles, n(S)=6+12=18

(a)Probability that the Marble is Red

$P(R)=\dfrac{n(R)}{n(S)} =\dfrac{12}{18} =\dfrac{2}{3}$

(b)Probability that the marble is odd-numbered.

Number of Odd-Numbered Balls, n(O)=9

$P(Odd)=\dfrac{n(O)}{n(S)} =\dfrac{9}{18} =\dfrac{1}{2}$

(c)Probability that the marble is red or odd-numbered.

n(Red)=12

n(Odd Numbered marbles)=9

n(Red and Odd Numbered Marbles)=6

$P(\text{Red or Odd Numbered})=P(Red)+P(Odd\:Numbered)-P(\text{Red and Odd Numbered)}\\=\dfrac{12}{18} +\dfrac{9}{18}-\dfrac{6}{18} =\dfrac{15}{18}\\P(\text{Red or Odd Numbered})=\dfrac{5}{6}$ (d)Probability that the marble is blue or even-numbered.

n(Blue)=6

n(Even Numbered marbles)=9

n(Blue and Even Numbered Marbles)=3

$P(\text{Blue or Even Numbered})=P(Blue)+P(Even\:Numbered)-P(\text{Blue and Even Numbered)}\\=\dfrac{6}{18} +\dfrac{9}{18}-\dfrac{3}{18} =\dfrac{12}{18}\\P(\text{Blue or Even Numbered})=\dfrac{2}{3}$

5 0

3 years ago