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Sauron [17]
4 years ago
14

A bird flies a velocity of 8 m/s ñ. How long does it take the bird to travel a horizontal distance of 400 meters?

Mathematics
1 answer:
sergejj [24]4 years ago
6 0

Answer:

50 seconds

Step-by-step explanation:

Well, if the bird is travelling 8 m/s then you divide 400 by 8 to figure out how long it would take it to fly, since 8 x 50= 400.

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Determine the length of the diagonals of the isosceles trapezoid below when KL= h+7 and UE= 4h-25
mina [271]

Answer:

KL= 17.67 unit

UE = 17.67 unit

Step-by-step explanation:

Given:

Diagonals

KL= h+7

UE = 4h-25

Find:

Length of diagonals KL and UE

Computation:

We know that in isosceles trapezoid the length of diagonals are equal

So,

KL = UE

h+7 = 4h-25

3h = 32

h = 10.67

So,

KL= h+7

KL= 10.67+7

KL= 17.67 unit

UE = 4h-25

UE = 4(10.67)-25

UE = 17.67 unit

6 0
3 years ago
If a machine produces 15 screws per​ minute, how many screws will it produce in 22 ​hours?
Sindrei [870]
15 × 60 = 900
900 × 22 = 19800

The answer is 19800 screws
5 0
3 years ago
5x + 4 = 7x i need help quick
anyanavicka [17]
5x + 4 = 7x

Subtract 4 from both sides.

5x = 7x - 4

Subtract 7x from both sides.

5x - 7x = -4

Simplify.

-2x = -4

Divide both sides by -2.

x = 4/2

x = 2

~Hope I helped!~
3 0
3 years ago
PLEASE HELP.
krek1111 [17]

Answer:

Part a) The radii are segments AC and AD and the tangents are the segments CE and DE

Part b) DE=4\sqrt{10}\ cm

Step-by-step explanation:

Part a)

we know that

A <u>radius</u> is a line from any point on the circumference to the center of the circle

A <u>tangent</u> to a circle is a straight line which touches the circle at only one point. The tangent to a circle is perpendicular to the radius at the point of tangency.

In this problem

The radii are the segments AC and AD

The tangents are the segments CE and DE

Part b)

we know that

radius AC is perpendicular to the tangent CE

radius AD is perpendicular to the tangent DE

CE=DE

Triangle ACE is congruent with triangle ADE

Applying the Pythagoras Theorem

AE^{2}=AC^{2}+CE^{2}

substitute the values and solve for CE

14^{2}=6^{2}+CE^{2}

CE^{2}=14^{2}-6^{2}

CE^{2}=160

CE=\sqrt{160}\ cm

CE=4\sqrt{10}\ cm

remember that

CE=DE

so

DE=4\sqrt{10}\ cm

7 0
3 years ago
How many planes exist that pass through points a,b ,and c
shusha [124]

1 because 3 points determine a plane.

6 0
3 years ago
Read 2 more answers
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