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swat32
3 years ago
9

(4x + 5)

Mathematics
1 answer:
zavuch27 [327]3 years ago
7 0

Answer:

<A = 133degrees

Step-by-step explanation:

Find the diagram attached

Using the theorem that "the sum of opposite angle of a cyclic quadilateral is 180 degrees, hence;

m<A + m<C = 180

4x+5 + x + 15 = 180

4x+x+5+15 = 180

5x+20 = 180

5x = 180 - 20

5x = 160

x = 160/5

x = 32degrees

Get the measure of angle A

<A = 4x+5

<A  = 4(32)+5

<A = 128+5

<A = 133degrees

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Escribe una ecuación de la recta que pasa por el punto (5, –8) con pendiente 5.
Nana76 [90]

Considerando la expresión de una ecuación lineal, la ecuación de la recta que pasa por el punto (5, –8) con pendiente 5 es y= 5x - 33.

<h3>Ecuación lineal</h3>

Una ecuación lineal o línea se puede expresar en la forma y = mx + b

donde

  • x y son coordenadas de un punto.
  • m es la pendiente.
  • b es la ordenada al origen y representa la coordenada del punto donde la línea cruza el eje y.

La ecuación lineal se puede expresar también mediante la ecuación punto-pendiente de la recta, que se plantea si se conoce la pendiente de la recta y cualquiera de sus puntos. Con ello queda determinada la recta, conociendo la pendiente  “m” y un punto  (x1, y1) dado:

y - y1= m(x -x1)

<h3>Ecuación de la recta en este caso</h3>

En este caso, la recta que pasa por el punto (5, –8) con pendiente 5.

Reemplazando en la ecuación punto-pendiente de la recta:

y - (-8)= 5(x -5)

Resolviendo:

y + 8= 5(x -5)

Aplicando propiedad distributiva:

y + 8= 5x - 5×5

y + 8= 5x - 25

Aislando la variable "y":

y= 5x - 25 - 8

<u><em>y= 5x - 33</em></u>

Finalmente, la ecuación de la recta que pasa por el punto (5, –8) con pendiente 5 es y= 5x - 33.

Aprende más sobre ecuación de una recta:

brainly.com/question/25243069

brainly.com/question/19260315

brainly.com/question/24766917

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