60 minutes is 20% of 300 minutes
hope i helped
1) 20x+5y=120
Stp1: 5y=120-20x
Stp2: 5y=(120/5 and -20x/5)= [y=24-4x]
finding x:
20x+5(24-4x)=120
Stp1: 5*24=120,-4x*5=-20
20x+120-20x=120
Stp2: subtract 120 on both sides of = sign
20x-20x=0
Stp3: subtract the variables:
[x=0]
finding y:
20(0)+5y=120
stp1: multiply 20*0
5y=120
stp2: divide 120 by 5
[y=24]
2) 10x+7.5y=80
Stp1: move 7.5y to other sign of =
10x=80-7.5y
Stp2: divide by 10
[x=8-.75y]
substitute x and re do original:
stp1: 10(8-.75y)+7.5y=80
stp2: 80-7.5y+7.5y=80
stp3: subtract variabled num. with variabled num. and whole num. with whole number: [y=0]
solve for x:
10x-7.5(0)=80
10x=80
[x=8]
check:
10(8)+7.5(0)=80
80+0=80
[80=80]
The answer for your problem is 1/3
Multiply the numerator of the first fraction by the denominator of the second fraction. Set this equal to the product of the denominator of the first fraction and the numerator of the second fraction.
7⋅9=p⋅8
Solve the equation for p.
p=63/8
Hope this helped! Let me know if you have any questions. Mark me Brianliest please:)
Answer: 1/4:1 1/4 = 2:b
↓
1/4 / 5/4 = 2/b
4/4 * 5 = 2/b
1/5 = 2/b
b/5 = 2
b = 2 * 5
b = 10
Step-by-step explanation:
