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3 years ago

900 is 4 1/2% of what?

2 answers:

3 0

Simple, first change the 4.5% into 0.045

Thus,

900=0.045*n

900/0.045=0.045n/0.045

20,000=n

Thus, your answer is 20,000.

Juli2301 [7.4K]3 years ago

3 0

900 = 4 1/2 % of what?

Let the what be x, 4 1/2% = 9/2% = (9/2)/100 = 9/200

900 = (9/200)*x

900 = 9x/200

9x = 900*200

x = (900*200)/9 = 20000

Therefore 900 is 4 1/2% of 20000

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Determine the time necessary for P dollars to double when it is invested at interest rate r compounded annually, monthly, daily,

Rudik [331]

Answer:

Part 1) 8.17 years

Part 2) 4.98 years

Part 3) 4.95 years

Part 4) 4.95 years

Step-by-step explanation:

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

Part 1) Determine the time necessary for P dollars to double when it is invested at interest rate r=14% compounded annually

in this problem we have

$t=?\ years\\ P=\$p\\A=\$2p\\r=14\%=14/100=0.14\\n=1$

substitute in the formula above

$2p=p(1+\frac{0.14}{1})^{t}$

$2=(1.14)^{t}$

Apply log both sides

$log(2)=log[(1.14)^{t}]$

$log(2)=(t)log(1.14)$

$t=log(2)/log(1.14)$

$t=8.17\ years$

Part 2) Determine the time necessary for P dollars to double when it is invested at interest rate r=14% compounded monthly

in this problem we have

$t=?\ years\\ P=\$p\\A=\$2p\\r=14\%=14/100=0.14\\n=12$

substitute in the formula above

$2p=p(1+\frac{0.14}{12})^{12t}$

$2=(\frac{12.14}{12})^{12t}$

Apply log both sides

$log(2)=log[(\frac{12.14}{12})^{12t}]$

$log(2)=(12t)log(\frac{12.14}{12})$

$t=log(2)/12log(\frac{12.14}{12})$

$t=4.98\ years$

Part 3) Determine the time necessary for P dollars to double when it is invested at interest rate r=14% compounded daily

in this problem we have

$t=?\ years\\ P=\$p\\A=\$2p\\r=14\%=14/100=0.14\\n=365$

substitute in the formula above

$2p=p(1+\frac{0.14}{365})^{365t}$

$2=(\frac{365.14}{365})^{365t}$

Apply log both sides

$log(2)=log[(\frac{365.14}{365})^{365t}]$

$log(2)=(365t)log(\frac{365.14}{365})$

$t=log(2)/365log(\frac{365.14}{365})$

$t=4.95\ years$

Part 4) Determine the time necessary for P dollars to double when it is invested at interest rate r=14% continuously

we know that

The formula to calculate continuously compounded interest is equal to

$A=P(e)^{rt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

e is the mathematical constant number

we have

$t=?\ years\\ P=\$p\\A=\$2p\\r=14\%=14/100=0.14$

substitute in the formula above

$2p=p(e)^{0.14t}$

Simplify

$2=(e)^{0.14t}$

Apply ln both sides

$ln(2)=ln[(e)^{0.14t}]$

$ln(2)=(0.14t)ln(e)$

Remember that ln(e)=1

$ln(2)=(0.14t)$

$t=ln(2)/(0.14)$

$t=4.95\ years$

4 0

3 years ago

In a small private school, five students are randomly selected from eighteen available students. What is the probability that t

guajiro [1.7K]

Answer:

1 / 8568

Step-by-step explanation:

The number of combinations is:

₁₈C₅ = (18! / (5! (18−5)!)

₁₈C₅ = 8568

There are 8568 possible groups of 5 that can be selected from 18. Only 1 of those groups contains the five youngest students. So the probability is:

P = 1 / 8568 ≈ 0.0117%

4 0

4 years ago

Help me please if u answer these i will love u forever

Genrish500 [490]

Answer:

1. Yes

2. No

3. Yes

4. No

5. Yes

6. No

1____I____1.95

2____I____3.90

3____I____5.85

4____I____7.80

1____I____1 1/3

2____I____2 2/3

3____I____4

4____I____5 1/3

1____I____62

4____I____248

7____I____434

9____I____558

10.

0.75____I____1.17

1.25____I____2.95

2____I____4.72

2.5____I____5.9

11.

2____I____1.6

4____I____3.2

6____I____4.8

8____I____6.4

12.

1____I____3 7/8

2____I____7 6/8

3____I____11 5/8

4____I____15 1/2

5 0

3 years ago

Y=-0.177x+43.49<br> y=-0.148x+39.84

sattari [20]

Answer:

use quizlet it should help

Step-by-step explanation:

3 0

3 years ago

Eduardo has purchased a home with an assessed value of $179,000. The property tax rate in his area is 2.3%. What is his monthly

ad-work [718]

Answer:

C. 343.08

Step-by-step explanation:

Convert the tax rate into a decimal and multiply by the house price:

.023(179,000) = 4,117

Divide by 12 (to get monthly rate):

4,117/12 ≈ 343.08

Option C should be the correct answer.

7 0

3 years ago