Actually, when you know 2 sides and an included angle, you use the Law of Cosines. (and we don't know if theta is an included angle).
Solving for side c
c^2 = a^2 + b^2 -2ab * cos(C)
c^2 = 36 + 16 - 2*6*4 * cos(60)
c^2 = 52 -48*.5
c^2 = 28
c = 5.2915
Using the Law of Sines
side c / sin(C) = side b / sin (B)
5.2915 / sin(60) = 4 / sin (B)
sin(B) = sin(60) * 4 / 5.2915
sin(B) = 0.86603 * 4 / 5.2915
<span><span>sin(B) = 3.46412
</span>
/ 5.2915
</span>
<span><span><span>sin(B) = 0.6546571451
</span>
</span>
</span>
Angle B = 40.894 Degrees
sin (A) / side a = sin (B) / side b
sin (A) = 6 * sin (40.894) / 4
sin (A) = 6 * 0.65466 / 4
sin (A) = .98199
angle A = 79.109 Degrees
angle C = 60 Degrees
Answer:
do you mean 50/360? if 50/360 it is 50 degrees
if 50/350 it is about 50/350*360 = 51.429 degrees
Answer:
To find the volume, we must find the area of the circle and multiply it by its height, think of a cylinder as an object made up of MANY circles. So, V=pir^2h... so diameter is 6cm so radius = 3cm...
therefore, Volume = (pi)(3^2)(12) = 108(pi)
where 12 = height 3 = radius
For the surface area, we need to find the area of the 2 circles(top and bottom ) so once again,
2(pi)(r^2) = 2(pi)(9)
for the area of the rectangle(if we unfold the cylindrical can) we get D(pi)(12) where D= Diameter
so the surface area is
SA = (2)(9)(pi) + 6(pi)(12)
SA = 18pi + 72pi = 90pi
Each box has twelve blue markers.. no i'm not 100% sure about this answer
