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Oksanka [162]
3 years ago
5

PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!! I CANNOT RETAKE THIS!!

Mathematics
2 answers:
Evgen [1.6K]3 years ago
5 0

Answer:

f(x)= log_3(x+2)-5

Step-by-step explanation:

Parent function is g(x)= log_3(x)

LEts pick a point from the graph and check with each option

LEts pick (-1,-5)

f(x)= log_3(x-2)-1

f(x)= log_3(-1-2)-1

log term cannot be negative

f(x)= log_3(x-3)-2

f(x)= log_3(-1-3)-2

log term cannot be negative

f(x)= log_3(x+2)-5

f(x)= log_3(-1+2)-5

f(x)= log_3(1)-5, log(1) is 0

f(x)= -5 that is the y value

(-1,-5) satisfies the above equation

olchik [2.2K]3 years ago
4 0

The answer to this is C

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If c= 205 angle A=81 and angle B=50. b=
zlopas [31]

Answer:

Solution to Problem 1:

Use the fact that the sum of all three angles of a triangle is equal to 180 o to write an equation in C.

A + B + C = 180 o

Solve for C.

C = 180 o - (A + B) = 43 o

Use sine law to write an equation in b.

a / sin(A) = b / sin(B)

Solve for b.

b = a sin (B) / sin(A) = (approximately) 5.4 cm

Use the sine law to write an equation in c.

a / sin(A) = c / sin(C)

Solve for c.

c = a sin (C) / sin(A) = (approximately) 7.1 cm

Problem 2

The angle of elevation to the top C of a building from two points A and B on level ground are 50 degrees and 60 degrees respectively. The distance between points A and B is 30 meters. Points A, B and C are in the same vertical plane. Find the height h of the building(round your answer to the nearest unit).

diagram problem 2

Solution to Problem 2:

We consider triangle ABC. Angle B internal to triangle ABC is equal to

B = 180 o - 60 o = 120 o

In the same triangle, angle C is given by.

C = 180 o - (50 o + 120 o) = 10 o

Use sine law to find d.

d / sin(50) = 30 / sin(10)

Solve for d.

d = 30 *sin(50) / sin(10)

We now consider the right triangle.

sin (60) = h / d

Solve for h.

h = d * sin(60)

Substitute d by the expression found above.

h = 30 *sin(50) * sin(60) / sin(10)

Use calculator to approximate h.

h = (approximately) 115 meters.

Problem 3

A triangle ABC has side a = 12 cm, side b = 19 cm and angle A = 80 o (angle A is opposite side a). Find side c and angles B and C if possible.(round answers to 1 decimal place).

Solution to Problem 3:

Use sine law to write an equation in sin(B).

a / sin(A) = b / sin(B)

Solve for sin(B).

sin (B) = (b / a) sin(A) = (19/12) sin(80) = (approximately) 1.6

No real angle B satisfies the equation

sin (B) = 1.6

The given problem has no solution.

Problem 4

A triangle ABC has side a = 14 cm, side b = 19 cm and angle A = 32 o (angle A is opposite side a). Find side c and angles B and C if possible.(round answers to 1 decimal place).

Solution to Problem 4

Use sine law to write an equation in sin(B).

a / sin(A) = b / sin(B)

Solve for sin(B).

sin (B) = (b / a) sin(A) = (19/14) sin(32) = (approximately) 0.7192

Two angles satisfy the equation sin (B) = 0.7192 and the given problem has two solutions

B1 = 46.0 o and B2 = 134 o

Solution 1: Find angle C1 corresponding to B1

C1 = 180 - B1 - A = 102 o

Solution 1: Find side c1 corresponding to C1

c1 / sin(C1) = a / sin(A)

c1 = 14 sin(102) / sin(32) = (approximately) 25.8 cm

Solution 2: Find angle C2 corresponding to B2

C2 = 180 - B2 - A = 14 o

Solution 2: Find side c2 corresponding to C2

c2 / sin(C2) = a / sin(A)

c1 = 14 sin(14) / sin(32) = (approximately) 6.4 cm

Exercises

1. A triangle ABC has angle A = 104 o, angle C = 33 o and side c = 9 m. Solve the triangle ABC by finding angle B and sides a and b.(round answers to 1 decimal place).

2. Redo problem 2 with the distance between points A and B equal to 50 meters.

Solutions to Above Exercises

1. B = 43 o, a = 16.0 m , b = 11.3 m

2. 191 meters.

More References and Links to Sine and Cosine Laws

sine law

Sine Law Calculator and Solver.

Geometry Tutorials, Problems and Interactive Applets.

Cosine Law Problems.

Cosine Law Calculator and Solver.

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Sine Law Calculator and Solver

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Triangles

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7 0
3 years ago
SOMEONE PLEASE ANSWER ASAP!! 55 POINTS!!
nadezda [96]

Answer:

EG = 16 and FH =22

Step-by-step explanation:

We know that the diagonals of a parallelogram bisect each other

so 2a  = 3b+2

and 2a+3 = 6b-1

We know have a system of equations to solve

2a  = 3b+2

 2a+3 = 6b-1

Subtract 3 from each side

2a+3-3 = 6b-1-3

2a = 6b -4

Now we can set the 2 equations equal  ( 2a  = 3b+2  and 2a = 6b -4)

3b+2 = 6b-4

Subtract 3b from each side

3b-3b+2 = 6b-3b-4

2 = 3b-4

Add 4 to each side

2+4 = 3b-4+4

6 = 3b

Divide by 3

6/3 = 3b/3

2 =b

We want to find a

2a  = 3b+2

Substitute in b=2

2a = 3(2) + 2

2a = 6+2

2a =8

Divide by 2

2a/2 =8/2

a = 4

Now that we know a and b

EG = 2a + 3b+2

    = 2(4) + 3(2)+2

   = 8+6+2

   = 16

FH = 2a+3 + 6b-1

    = 2(4) +3 +6(2)-1

    = 8+3+12-1

   = 23-1

  = 22

4 0
3 years ago
Evaluate the expression when <br> a = -4 and x=5.<br><br> -5a +x
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Answer:

Step-by-step explanation:

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