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mario62 [17]
3 years ago
7

You have 8 hats and sell them for $4 each. How money would you have if you sold only 2 of the hats?

Mathematics
2 answers:
OlgaM077 [116]3 years ago
6 0
8 dollars because you sold them for 4 dollars each and only sold two. 4x2=8
zepelin [54]3 years ago
6 0

Solution

Isn't it just 2 * 4 = 8 dollars.? I almost figured it out using the 8 hats. Nice trick.

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4. Which of the following describes all the solutions of -4x + 2y > 12 when y = 4?
Alja [10]

Answer:

Option B is correct

Step-by-step explanation:

Given data

We are given the expression

-4x + 2y > 12

We want to substitute y=4 into the expression

-4x + 2(4) > 12

-4x + 8 > 12

-4x> 12-8

-4x> 4

divide both sides by -4

x> 4/-4

x>-1

Hence option B is correct

5 0
2 years ago
Please help i will mark brainliest
barxatty [35]

Answer:

2

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
I need help with questions #7 and #8 plz
katen-ka-za [31]

Answer:

7. A = 40.8 deg; B = 60.6 deg; C = 78.6 deg

8. A = 20.7 deg; B = 127.2 deg; C = 32.1 deg

Step-by-step explanation:

Law of Cosines

c^2 = a^2 + b^2 - 2ab \cos C

You know the lengths of the sides, so you know a, b, and c. You can use the law of cosines to find C, the measure of angle C.

Then you can use the law of cosines again for each of the other angles. An easier way to solve for angles A and B is, after solving for C with the law of cosines, solve for either A or B with the law of sines and solve for the last angle by the fact that the sum of the measures of the angles of a triangle is 180 deg.

7.

We use the law of cosines to find C.

18^2 = 12^2 + 16^2 - 2(12)(16) \cos C

324 = 144 + 256 - 384 \cos C

-384 \cos C = -76

\cos C = 0.2

C = \cos^{-1} 0.2

C = 78.6^\circ

Now we use the law of sines to find angle A.

Law of Sines

\dfrac{a}{\sin A} = \dfrac{b}{\sin B} = \dfrac{c}{\sin C}

We know c and C. We can solve for a.

\dfrac{a}{\sin A} = \dfrac{c}{\sin C}

\dfrac{12}{\sin A} = \dfrac{18}{\sin 78.6^\circ}

Cross multiply.

18 \sin A = 12 \sin 78.6^\circ

\sin A = \dfrac{12 \sin 78.6^\circ}{18}

\sin A = 0.6535

A = \sin^{-1} 0.6535

A = 40.8^\circ

To find B, we use

m<A + m<B + m<C = 180

40.8 + m<B + 78.6 = 180

m<B = 60.6 deg

8.

I'll use the law of cosines 3 times here to solve for all the angles.

Law of Cosines

a^2 = b^2 + c^2 - 2bc \cos A

b^2 = a^2 + c^2 - 2ac \cos B

c^2 = a^2 + b^2 - 2ab \cos C

Find angle A:

a^2 = b^2 + c^2 - 2bc \cos A

8^2 = 18^2 + 12^2 - 2(18)(12) \cos A

64 = 468 - 432 \cos A

\cos A = 0.9352

A = 20.7^\circ

Find angle B:

b^2 = a^2 + c^2 - 2ac \cos B

18^2 = 8^2 + 12^2 - 2(8)(12) \cos B

324 = 208 - 192 \cos A

\cos B = -0.6042

B = 127.2^\circ

Find angle C:

c^2 = a^2 + b^2 - 2ab \cos C

12^2 = 8^2 + 18^2 - 2(8)(18) \cos B

144 = 388 - 288 \cos A

\cos C = 0.8472

C = 32.1^\circ

8 0
2 years ago
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ziro4ka [17]
So hmmm notice the picture below

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5 0
3 years ago
Plz help Arithmetic Sequence
IgorC [24]

Answer:

it is a+b-6x

Step-by-step explanation:

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