A=3 b=5 c=2
x = -b +-sq root(b^2 -4*a*c) / 2a
x = [-5 +-sq root(5^2 -4*3*2)] / 6
x = [-5 +-sq root(25 -24)]/6
x = [-5 +- 1] /6
x1 = -1
x2 = -4/6 = -2/3 = -.66666666666666
15 - 4 1/3 = 10 2/3
10 2/3 * 3/5 = 6 4/10
10 2/3 - 6 4/10 = 4 4/15
Answer:
27 = 2r
13.5 =r
Step-by-step explanation:
We know that the diameter is twice the radius
d = 2r
27 = 2r
Divide by 2
27/2 = 2r/2
13.5 = r
A6 = -8
a15= -62
There are (15 - 6) terms in between, therefore 9 terms in between.
-8 to -62 ... there is a difference of 54
54 ÷ 9 = 6
Therefore it gets -6 each term.
a6 = -8, a7= -14, a8 = -20 ......
The points in the graph are (-1,0) and (3,0). I solved the equation using the Factoring method in solving quadratic equations. As I solved for finding x= -1 and 3, I substituted both to the equation in order to find y.