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4 years ago

Point slope y-7=2/9x-3

Mathematics

1 answer:

elena55 [62]4 years ago

8 0

The slope is the value in the term with "x". That is 2/9x has "x".

In this case, the slope will be 2/9

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Celia writes the addition problem shown.she says she can tell which sum will be greater without adding.how does she know?

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3 years ago

7/8 times 1 2/3 I need the work

BaLLatris [955]

$\frac{7}{8} * 1\frac{2}{3}$ can be rewritten as $\frac{7}{8} * \frac{5}{3}$ which is $\frac{7 * 5}{8* 3}$ , which simplifies into $\frac{35}{24}$ or $1\frac{11}{24}$ .

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3 years ago

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A carpenter can build a cabinet in three hours at this rate how long will it take for the carpenter to build 26 cabinets

Ludmilka [50]

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3 years ago

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3 years ago

The Pew Internet and American Life Project reported Wednesday, April 18th that two- thirds (67%) of young adults with profiles o

dlinn [17]

Answer:

At 5% significance level, larger proportion of military personnel students protect their profiles on social-networking sites than young adults with profiles on social-networking sites.

Step-by-step explanation:

let p be the proportion of military personnel students who restrict access to their profiles. Then null and alternative hypotheses are:

$H_{0}$ : p=0.67 (67%)

$H_{a}$ : p>0.67

We need to calculate z-statistic of sample proportion:

z= $\frac{p(s)-p}{\sqrt{\frac{p*(1-p)}{N} } }$ where

p(s) is the sample proportion of military students who restrict access to their profiles ( $\frac{78}{100}$ =0.78)

p is the proportion assumed under null hypothesis. (0.67)

N is the sample size (100)

Then z= $\frac{0.78-0.67}{\sqrt{\frac{0.67*0.33}{100} } }$ ≈ 2.34

The corresponding p-value is 0.0096. Since 0.0096<0.05 (significance level) we can reject the null hypothesis and conclude at 5% significance level that larger proportion of military personnel students protect their profiles on social-networking sites than young adults with profiles on social-networking sites.

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3 years ago