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nlexa [21]
3 years ago
10

A snow storm dumped `8 inches in a 12 hour period. how many inches where falling per hour?

Mathematics
2 answers:
chubhunter [2.5K]3 years ago
8 0
0.6666... inches were falling per hour.
In order to solve this question you have to divide 8 by 12. You will get 0.66666....
Softa [21]3 years ago
7 0
8 inches/12h = ?/1h
cross product: 8 X 1 / 12 = ?
8/12= 0,6666 (or 2/3) inch
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A and B are partners sharing profit and loss in the ratio of 3:2. A new partner C is admitted and 1/4 share off profit is given.
Gre4nikov [31]

Answer:

Correct option is: 9:6:5

Step-by-step explanation:

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6 0
3 years ago
Lesson: 1.08Given this function: f(x) = 4 cos(TTX) + 1Find the following and be sure to show work for period, maximum, and minim
Ber [7]

The given function is

f(x)=4\cos \text{(}\pi x)+1

The general form of the cosine function is

y=a\cos (bx+c)+d

a is the amplitude

2pi/b is the period

c is the phase shift

d is the vertical shift

By comparing the two functions

a = 4

b = pi

c = 0

d = 1

Then its period is

\begin{gathered} \text{Period}=\frac{2\pi}{\pi} \\ \text{Period}=2 \end{gathered}

The equation of the midline is

y_{ml}=\frac{y_{\max }+y_{\min }}{2}

Since the maximum is at the greatest value of cos, which is 1, then

\begin{gathered} y_{\max }=4(1)+1 \\ y_{\max }=5 \end{gathered}

Since the minimum is at the smallest value of cos, which is -1, then

\begin{gathered} y_{\min }=4(-1)+1 \\ y_{\min }=-4+1 \\ y_{\min }=-3 \end{gathered}

Then substitute them in the equation of the midline

\begin{gathered} y_{ml}=\frac{5+(-3)}{2} \\ y_{ml}=\frac{2}{2} \\ y_{ml}=1 \end{gathered}

The answers are:

Period = 2

Equation of the midline is y = 1

Maximum = 5

Minimum = -3

3 0
1 year ago
Solve for X: <br> 5(2x-12)=140
Mrac [35]

Answer:

x=20

Step-by-step explanation:

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x=20

6 0
4 years ago
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solong [7]
5

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4 0
3 years ago
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polet [3.4K]

Answer:

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Step-by-step explanation:

7 0
3 years ago
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