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kherson [118]
3 years ago
5

Solve the equation graphically by finding intersections. |2x+1|=17 X=

Mathematics
1 answer:
makvit [3.9K]3 years ago
7 0
X equals 8, because you multiply 2 times 8 then add 1
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The function f is defined by f(x)=2.1x−1.7. Use this formula to find the following values of f. f(x+2)
Yuki888 [10]

The value of f(x+2)=2.1x+2.5

Step-by-step explanation:

Given: The function f(x)=2.1x-1.7

Using this formula, we need to find the value of f(x+2)

Hence, we need to substitute x by x+2 to find the value of f(x+2)

f(x+2)=2.1(x+2)-1.7

Multiplying the term (x+2) by 2.1, we get,

f(x+2)=2.1x+4.2-1.7

Adding the constant term,

f(x+2)=2.1x+2.5

Thus, the value of f(x+2) is f(x+2)=2.1x+2.5

8 0
2 years ago
Blossom typed 1/8 of her report on Monday. She typed 1/4 of the report of Tuesday. How much of the report does she need to type
DochEvi [55]

Answer:4

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Solve for x: 3+(-5)x=19
malfutka [58]
3+(-5)x=19
Subtract 3 from both sides of the equation.
-5x= 16
Divide by -5 on both sides
X= -3.2
4 0
3 years ago
Read 2 more answers
A computer system uses passwords that are six characters, and each character is one of the 26 letters (a–z) or 10 integers (0–9)
Blababa [14]

First of all, since we have 36 characters available per spot (26 letters and 10 digits), and we have 6 spots, we have a total of

36^6

possible passwords.

Event A happens if the password starts with either a, e, i, o or u. If we fix the first character, we're left with 36 characters available for each of the remaining 5 spots, leading to a total of

5\cdot 36^5

possible passwords.

So, the probability of event A, computed as the ratio between "good" cases and all possible cases, is

\dfrac{5\cdot 36^5}{36^6}=\dfrac{5}{36}

Event B works exactly the same, since we're fixing the last spot, leaving 36 characters available for each of the first 5 spots. So, we have

P(A)=P(B)=\dfrac{5}{36}

As for the intersection, we want the first character to be a vowel, and the last character to be an even digits. There are 25 passwords satisfying this request:

axxxx0,\ axxxx2,\ axxxx4,\ axxxx6,\ axxxx8

exxxx0,\ exxxx2,\ exxxx4,\ exxxx6,\ exxxx8

ixxxx0,\ ixxxx2,\ ixxxx4,\ ixxxx6,\ ixxxx8

oaxxxx0,\ oxxxx2,\ oxxxx4,\ oxxxx6,\ oxxxx8

uxxxx0,\ uxxxx2,\ uxxxx4,\ uxxxx6,\ uxxxx8

Where x can be any of the 36 characters.

So, we have 25 cases with 4 vacant slots, leading to a probability of

P(A\cap B)=\dfrac{25\cdot 36^4}{36^6}=\dfrac{25}{1296}

Finally, you can compute the probability of the union using the formula

P(A\cup B)=P(A)+P(B)-P(A\cap B)

Since we already computed all these quantities.

7 0
2 years ago
What are the coordinates of the image of vertex D after a reflection across the x-axis?
alex41 [277]

Answer:

Where is the image

Step-by-step explanation:

3 0
3 years ago
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