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3 years ago

5

What is the distance between the points (-3, 2) and (1,0)?

2 answers:

sleet_krkn [62]3 years ago

7 0

the difference is (4,-1)

grigory [225]3 years ago

6 0

The answer would be (4-1)

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Which binomials are a difference of squares?

kow [346]

Answer:

Options B and C.

Step-by-step explanation:

Difference of squares is defined as

$a^2-b^2$

where, a and b both area real numbers.

$y^4+9\Rightarrow (y^2)^2+3^2$

It is sum of squares.

$9x^2-16\Rightarrow (3x)^2-4^2$

It is difference of squares.

$m^6-25\Rightarrow (m^3)^2-5^2$

It is difference of squares.

$m^7-1\Rightarrow m^7-1^2$

It is not a difference of squares.

Therefore, the correct options are B and C.

3 0

4 years ago

VikaD [51]

Answer:

1. p>10

open circle on 10 arrow pointing right

2. c<-2

open circle on 2 arrow pointing left

3. m<-50

open circle on -50 arrow pointing left

4. z<-7

open circle on -7 arrow pointing left

7 0

4 years ago

Can someone help me pleaseeeeeeeeee ASAP

lord [1]

Answer:

18/23

Step-by-step explanation:

36/46

then simplified to 18/23

5 0

3 years ago

Read 2 more answers

What are the first three terms of a geometric sequence in which as = 25 and the common ratio is 5?

marin [14]

Answer:

The first three terms are: 25, 125 and 625

Step-by-step explanation:

Given

$a =25; r = 5$

Required

The first three terms

The nth term of a geometry progression is:

$T_n =ar^{n-1$

So, we have:

First term: $n = 1$

$T_n =ar^{n-1$

$T_1 =25 * 5^{1-1$

$T_1 =25 * 5^0$

$T_1 =25 * 1$

$T_1 =25$

Second term: $n = 2$

$T_n =ar^{n-1$

$T_2 =25 * 5^{2-1$

$T_2 =25 * 5^{1$

$T_2 =25 * 5$

$T_2 =125$

Third term: $n = 3$

$T_n =ar^{n-1$

$T_3 =25 * 5^{3-1$

$T_3 =25 * 5^{2$

$T_3 =25 * 25$

$T_3 =625$

7 0

3 years ago

F(x)= <br> 2x <br> 2<br> −x−15<br> −4x+12<br>

Zinaida [17]

Answer:

f(x) = -x -3

Step-by-step explanation:

5 0

3 years ago